我有两个类别列出性别和品牌。第一类
<ul>
<li><input type="checkbox" id="checkboxa" class="chkbox" value="url.php?gender=children" name="gender"> Kid</li>
<li><input type="checkbox" id="checkboxb" class="chkbox" value="url.php?gender=male" name="gender"> Male</li>
<li><input type="checkbox" id="checkboxc" class="chkbox" value="url.php?gender=female" name="gender"> Female</li>
</ul>
第二类
<ul>
<li><input type="checkbox" id="checkbox1" class="chkbox" value="url.php?barnd=brand1" name="brand"> Brand1</li>
<li><input type="checkbox" id="checkbox2" class="chkbox" value="url.php?barnd=brand2" name="brand"> Brand2</li>
<li><input type="checkbox" id="checkbox3" class="chkbox" value="url.php?barnd=brand3" name="brand"> Brand3</li>
<li><input type="checkbox" id="checkbox4" class="chkbox" value="url.php?barnd=brand4" name="brand"> Brand4</li>
</ul>
这是我的js:
<script>
$(document).ready(function() {
$('.chkbox').on('change', function() {
if ($(this).is(':checked')) {
var url = $(this).val();
console.log(url);
window.location = url;
}
});
});
</script>
现在,当检查一个项目时,我的页面正在重新加载。我想只在选中每个类别的一个项目时才重新加载页面。 Plz帮助...... 在此先感谢.....
PS:url应该像url.php?brand = $ brand&amp;&amp; gender = $ gender $: - 已检查
答案 0 :(得分:2)
将您的if条件更改为
.val("")
OneSignal.inFocusDisplayType = OSNotificationDisplayType.none
if($("input[name='gender']:checked").length && $("input[name='brand']:checked").length) {
var url = $(this).val();
window.location = url;
}
答案 1 :(得分:2)
以下是摘录。
$(document).ready(function() {
$('#fcat .chkbox').on('change', function() {
if ($(this).is(':checked')) {
var url = $(this).val();
if ($(this).is(':checked')) {
if ($('.cat').is(':checked')) {
alert(url);
window.location = url;
}else{
alert('Select gender!');
}
}
}
});
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li><input type="checkbox" id="checkboxa" class="cat" value="url.php?gender=children" name="gender"> Kid</li>
<li><input type="checkbox" id="checkboxb" class="cat" value="url.php?gender=male" name="gender"> Male</li>
<li><input type="checkbox" id="checkboxc" class="cat" value="url.php?gender=female" name="gender"> Female</li>
</ul>
<ul id="fcat">
<li><input type="checkbox" id="checkbox1" class="chkbox" value="url.php?barnd=brand1" name="brand"> Brand1</li>
<li><input type="checkbox" id="checkbox2" class="chkbox" value="url.php?barnd=brand2" name="brand"> Brand2</li>
<li><input type="checkbox" id="checkbox3" class="chkbox" value="url.php?barnd=brand3" name="brand"> Brand3</li>
<li><input type="checkbox" id="checkbox4" class="chkbox" value="url.php?barnd=brand4" name="brand"> Brand4</li>
</ul>
&#13;
如果您选中性别复选框并选择品牌,则会重新加载您的品牌位置,然后返回提醒以选择性别优先。希望这能帮到你!
问候!
答案 2 :(得分:1)
<ul>
<li><input type="checkbox" id="checkboxa" class="chkbox chkType1" value="url.php?gender=children" name="gender"> Kid</li>
<li><input type="checkbox" id="checkboxb" class="chkbox chkType1" value="url.php?gender=male" name="gender"> Male</li>
<li><input type="checkbox" id="checkboxc" class="chkbox chkType1" value="url.php?gender=female" name="gender"> Female</li>
</ul>
<ul>
<li><input type="checkbox" id="checkbox1" class="chkbox chkType2" value="url.php?barnd=brand1" name="brand"> Brand1</li>
<li><input type="checkbox" id="checkbox2" class="chkbox chkType2" value="url.php?barnd=brand2" name="brand"> Brand2</li>
<li><input type="checkbox" id="checkbox3" class="chkbox chkType2" value="url.php?barnd=brand3" name="brand"> Brand3</li>
<li><input type="checkbox" id="checkbox4" class="chkbox chkType2" value="url.php?barnd=brand4" name="brand"> Brand4</li>
</ul>
和javascript:
<script>
$(document).ready(function() {
$('.chkbox').on('change', function() {
if ($(this).is(':checked')) {
if(($('.chkType1').length > 0 && $('.chkType2').length > 0))
{
var url = $(this).val();
url += '?brand='+$($('.chkType1')[0]).val()+'&&gender=' + $($('.chkType2')[0]).val();
console.log(url);
window.location = url;
}
}
});
});
</script>