我正在尝试使用模板类(此处为Foo
),基本类型如下:
hana::tuple<hana::pair<hana::type<int>, Runtime>>
Runtime
一个类,其中不可能是constepxr
。但是这种类型可以用几种方式构造,这就是我使用的原因:
hana::tuple<hana::pair<hana::type<int>, hana::type<Runtime>>>
在编译时完成工作。 所以问题基本上是如何从第一个元组转换为第二个 。我想知道hana
中是否有某些东西可以帮助我。或者甚至更好,关于那种“转换”的一些提示。
namespace hana = boost::hana;
using namespace hana::literals;
struct Runtime { std::vector<int> data; };
template < typename T >
struct Foo {
T data;
};
constexpr decltype(auto) convertMap(auto storageMap) {
return hana::make_type(hana::transform(
storageMap,
[] (auto pair) {
return hana::make_pair(
hana::first(pair),
typename decltype(hana::typeid_(hana::second(pair)))::type {});
}));
}
int main() {
constexpr auto map = hana::make_tuple(
hana::make_pair(hana::type_c<int>, hana::type_c<Runtime>)
);
constexpr auto result = convertMap(map);
static_assert(result ==
hana::type_c<hana::tuple<hana::pair<hana::type<int>, Runtime>>>);
Foo<typename decltype(result)::type> test;
}
正如您所看到的,我尝试了一些带有convertMap
和hana::transform
的c ++ 1z lambdas
,但第二个元组不能是constexpr
,所以我可以'将其传递给hana::make_type
希望获得hana::type_c
。
test.cpp: In function ‘int main()’:
test.cpp:70:41: error: ‘constexpr decltype(auto) convertMap(auto:27) [with auto:27 = boost::hana::tuple<boost::hana::pair<boost::hana::type_impl<int>::_, boost::hana::type_impl<Runtime>::_> >]’ called in a constant expression
constexpr auto result = convertMap(map);
^
test.cpp:53:27: note: ‘constexpr decltype(auto) convertMap(auto:27) [with auto:27 = boost::hana::tuple<boost::hana::pair<boost::hana::type_impl<int>::_, boost::hana::type_impl<Runtime>::_> >]’ is not usable as a constexpr function because:
constexpr decltype(auto) convertMap(auto storageMap) {
^~~~~~~~~~
test.cpp:53:27: error: temporary of non-literal type ‘boost::hana::tuple<boost::hana::pair<boost::hana::type_impl<int>::_, Runtime> >’ in a constant expression
In file included from /usr/include/boost/hana/detail/struct_macros.hpp:29:0,
from /usr/include/boost/hana/adapt_adt.hpp:15,
from lib/hana/include/boost/hana.hpp:59,
from test.cpp:1:
/usr/include/boost/hana/tuple.hpp:68:12: note: ‘boost::hana::tuple<boost::hana::pair<boost::hana::type_impl<int>::_, Runtime> >’ is not literal because:
struct tuple
^~~~~
/usr/include/boost/hana/tuple.hpp:68:12: note: ‘boost::hana::tuple<boost::hana::pair<boost::hana::type_impl<int>::_, Runtime> >’ has a non-trivial destructor
答案 0 :(得分:6)
您所关心的只是一种类型 - 因此您可以隐藏非constexpr
实现函数中的类型计算,然后使用template <typename T>
decltype(auto) convertMapImpl(T storageMap)
{
return hana::make_type(hana::transform(storageMap, [](auto pair) {
return hana::make_pair(hana::first(pair),
typename decltype(hana::typeid_(hana::second(pair)))::type{});
}));
}
template <typename T>
constexpr decltype(auto) convertMap(T storageMap)
{
return decltype(convertMapImpl(storageMap)){};
}
将其调用到&#34;强制auto
&#34; :
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另请注意,在函数签名中使用Xdefaults
是gcc扩展名 - 您应该使用模板参数来代替标准。