Question

我有time1 = '09:00 AM'和time2 = '06:30 PM'。我如何使用moment.js减去这两个，这样我得到了result = 9hrs 30mins。

我在互联网上搜索但找不到合适的解决方案。任何建议都非常感谢。

Answer 1

我建议您编写自己的自定义函数，将时间转换为24小时，如果是PM则添加12小时，如果是AM则添加0。然后它将时间转换为分钟，减去两次，然后将它们转换回HH：MM AM / PM。

（伪代码（读起来有点像javascript））

//ap = am or pm; 0 for am, 1 for pm
define "subtractTimes" (time1, time1ap, time2, time2ap):

    //gets the length of time1 and time2
    set "time1Length" to (length(time1))
    set "time2Length" to (length(time2))

    //adds 12 hours if pm, converted to minutes
    set "time1InMinutes" to (time1ap * (12 * 60))
    set "time2InMinutes" to (time2ap * (12 * 60))

    //gets minutes from time1 and time2
    //You'd have to program your own function "getLetters"
    //Unless there's one that I'm unaware of. 
    set "time1MM" to (getLetters(time1,(time1Length-1),time1Length))
    set "time2MM" to (getLetters(time2,(time2Length-1),time2Length))


    //this script makes sure the times are the proper length.
    if "time1Length" = (4)
        set "time1" to (("0")join(time1)
    if "time2Length" = (4)
        set "time2" to (("0")join(time2)

    //gets hours from time1 and time 2
    set "time1HH" to (getLetters(time1,(time1Length-4),time1Length-3))
    set "time2HH" to (getLetters(time2,(time2Length-4),time2Length-3))

    //puts it all together
    set "time1InMinutes" to (time1InMinutes+(time1HH*60)+time1MM)
    set "time2InMinutes" to (time2InMinutes+(time2HH*60)+time2MM)
    set "newTimeInMinutes" to ((time1InMinutes)-(time2InMinutes))

    //converts it to HH:MM AM/PM
    set "newTime" to (floor(newTimeInMinutes/60))
    set newTimeInMinutes" to (newTimeInMinutes-(newTime*60))
    if "newTime" > (12): 
        set "newTime" to (newTime-12)
        set "ap" to (AM)
    else
        set "ap" to (PM)
    set "newTime" to ((newTime)join(":")join(newTimeInMinutes))
    set "newTime" to ((newTime)join(" ")join(ap)

    //end

这应该有效。如果您有任何疑问，请随时提出。

我们如何用时刻减去时间，js？

1 个答案: