Question

我的RSS说明如下：

＆＃39;描述：＆lt; a href =＆＃34; http：//www.afaqs.com/news/story/50219_Management-changes-at-Disney-Vijay-Subramaniam-quits-Abhishek-Maheshwari- to-head-Disney-Media＆＃34;＆gt;＆lt; img src =＆＃34; http：//www.afaqs.com/all/news/images/news_story_grfx/2017/50219_1_home_small.jpg" ALT =＆＃34; ＆＃34; HSPACE =＆＃34; 5＆＃34; ALIGN =＆＃34;左＆＃34;宽度=＆＃34; 59＆＃34;高度=＆＃34; 59＆＃34;边界=＆＃34; 0＆＃34; /＆GT;＆LT; / A＆GT;该网络还将Sanjeet Mehta提升为迪士尼消费品行业的负责人。＆＃39;

我必须在jquery中从中提取img src。

Answer 1

考虑这种方法：

使用ID创建div元素。
在您的javascript代码中，将InnerHTML值设置为div，其值为description。
使用querySelectorAll并获取图像的来源。

示例：

＆＃13;

id

＆＃13;

var description = 'description: <a href="http: //www.afaqs.com/news/story/50219_Management-changes-at-Disney-Vijay-Subramaniam-quits-Abhishek-Maheshwari-to-head-Disney-Media"><img src="http://www.afaqs.com/all/news/images/news_story_grfx/2017/50219_1_home_small.jpg" alt=" " hspace="5" align="left" width="59" height="59" border="0"/></a> The network has also elevated Sanjeet Mehta as head of Disney Consumer Products.';

// Set InnerHTML values:
document.getElementById('myDiv').innerHTML = description;

// Get src:
var mySrcValue = document.querySelectorAll('#myDiv > a > img')[0].src;

// Show src value:
document.getElementById('myResult').innerHTML = "<b>" + mySrcValue + "</b>";

＆＃13;

Answer 2

你不需要jquery这样做，javascript就足够了。您可以使用一行代码（split和regex）提取src属性：

var result = description.split('img')[1].split('alt')[0].match( /"(.*?)"/ )[1];

var description = 'description: <a href="http: //www.afaqs.com/news/story/50219_Management-changes-at-Disney-Vijay-Subramaniam-quits-Abhishek-Maheshwari-to-head-Disney-Media"><img src="http://www.afaqs.com/all/news/images/news_story_grfx/2017/50219_1_home_small.jpg" alt=" " hspace="5" align="left" width="59" height="59" border="0"/></a> The network has also elevated Sanjeet Mehta as head of Disney Consumer Products.';

result.innerHTML = description.split('img')[1].split('alt')[0].match( /"(.*?)"/ )[1];

<div id="result"></div>

从javascript中的rss描述中提取src

2 个答案: