Question

我正在为SalesForce api创建访问令牌，当我通过http.post（）发送请求时，我收到错误，如Bad Requests 400。这是我的代码：

getToken():Observable<any[]>{
       this.body={grant_type:'password',client_id:'3MVG9d8..57qfn8zsI8Du1zalkfIOVSz0qw_6Way_SrP6fP1apM3Pges9bhahYwdg.',client_secret:'5035130443686',username:'user@demo.com',password:'blabla'};
this.body2=JSON.stringify(this.body);
 let headers = new Headers({"Content-Type": "application/json"});
        let options = new RequestOptions({ headers});

       this.authorization = this.http.post("https://demo-dev-ed.my.salesforce.com/services/oauth2/token",this.body2,options)
       .map((res:any) => res.json());

       return this.authorization;


    }

但下面的代码完美无缺：

getToken():Observable<any[]>{

      var body="grant_type=password&client_id=3MVG9d8..z.Sz0qw_6Way_SrP6fP1apM3Pges9bhahYwdg.&client_secret=50351305443686&username=user@demo.com&password=blabla";

 let headers = new Headers({"Content-Type": "application/x-www-form-urlencoded"});

        let options = new RequestOptions({ headers});

       this.authorization = this.http.post("https://demo-dev-ed.my.salesforce.com/services/oauth2/token",this.body,options)
       .map((res:any) => res.json());

       return this.authorization;

    }

但是我想运行代码的第一部分。不管是什么问题！

Answer 1

尝试在不使用JSON.stringify(this.body);的情况下运行您的第一个代码将this.body直接发送到post方法。

Answer 2

JSON.stringify不会将params对象转换为正确的格式。您需要使用自定义功能。见the working plunker。它返回invalid_client_id，更改凭据。

  getToken():Observable<any[]>{
    const body = {grant_type:'password',client_id:'3MVG9d8..57qfn8zsI8Du1zalkfIOVSz0qw_6Way_SrP6fP1apM3Pges9bhahYwdg.',client_secret:'5035130443686',username:'user@demo.com',password:'blabla'};
    const bodyStr = this.buildString(body);
    let headers = new Headers({"Content-Type": "application/x-www-form-urlencoded"});

    this.authorization = this.http.post("https://demo-dev-ed.my.salesforce.com/services/oauth2/token", bodyStr, { headers: headers })
     .map((res:any) => res.json());

     return this.authorization;

  }

  buildString(obj) {
    var str = [];
    for(var p in obj)
      str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
    return str.join("&");
  }

http.post（）方法错误的请求问题

2 个答案: