Question

我有给定的数组

[ [ [ 'One' ], [ 'First', 'Fourth', 'Third' ] ],
  [ [ 'Three' ], [ 'First', 'Third' ] ],
  [ [ 'Two' ], [ 'First', 'Second', 'Third' ] ],
  [ [ 'One three' ], [ 'Fourth', 'Third' ] ],
  [ [ 'One two' ], [ 'Fourth', 'Second', 'Third' ] ],
  [ [ 'One two three' ], [ 'Second', 'Third' ] ] ]

我希望在javascript中按顺序对其进行排序：

[[["One"],["First","Fourth","Third"]], 
 [["One three"],["Fourth","Third"]], 
 [["One two"],["Fourth","Second","Third"]], 
 [["One two three"],["Second","Third"]], 
 [["Three"],["First","Third"]], 
 [["Two"],["First","Second","Third"]]]

我的信念是，一个简单的.sort（）调用就可以了。查看w3schools documentation on .sort()，它说

默认情况下，sort（）方法将值排序为字符串按字母顺序排列。

因此，我认为持有子子阵列['One']的子阵列将位于顶部。

然而，我的输出结果是：

[[["One three"],["Fourth","Third"]], 
 [["One two three"],["Second","Third"]], 
 [["One two"],["Fourth","Second","Third"]], 
 [["One"],["First","Fourth","Third"]], 
 [["Three"],["First","Third"]], 
 [["Two"],["First","Second","Third"]]]

为什么会这样？为什么[“One”]排在第4位而不是之前的3位？我不知道如何通过词典编纂推理。我甚至在控制台中检查了["One"] < ["One three"]并返回true。

我熟悉将自定义排序函数作为可选参数传递给.sort（）函数的技巧，但我的期望是没有必要。希望得到一个解释，并且可能需要指导哪些自定义排序功能是合适的。

更新：根据下面的有用评论，我现在看到我原来的直觉是错误的。将以下函数传递给.sort（）就可以了。

function sortFunction(a, b){
  if (a[0] < b[0]){
    return -1;
  } else if (a[0] > b[0]){
    return 1;
  } else {
    return 0;
  }
}

为什么.sort（）产生我的输出？

0 个答案: