Question

我尝试整合“＆＃39;单位＆＃39;和＆＃39;金额＆＃39;用于删除已反转的行项目（苹果）的字段，但它还将其他行项目（Pears）分组，我需要在单独的行中列出。有没有办法在不使用聚合函数的情况下删除反转的行项目？

SELECT Account, Code, Item, SUM(Units) As ‘Total Units’, SUM(Amount) AS ‘TotalAmt’
FROM Fruit
GROUP BY Account, Code, Item

表

Account    Code      Item   Units   Amount
-------  --------   ------- -----   ------
10325      5972      Apple  1   .50
10325      5972      Apple  -1     -.50
10325      7231      Pear   1   .62
10325      7231      Pear   1   .62
10431      5972      Apple  1   .50

RESULT

TABLE
Account    Code      Item   Units   Amount
-------  --------   ------- -----   ------
10325      7231      Pear   2   1.24
10431      5972      Apple  1   .50

Answer 1

试试这段代码：

SELECT Account, Code, Item, SUM(Units) As ‘Total Units’, SUM(Amount) AS ‘TotalAmt’
FROM Fruit
GROUP BY Account, Code, Item
having sum(Units)>0

Answer 2

假设我们有可用的窗口函数，我们可以创建按帐户，项目单位和金额划分的行号，在这些字段上加入然后加入RowNumber，这样我们就不会为多个销售分配回报。

回报可能与错误的销售有关，所以我不喜欢这种回应;但如果我们不关心这一点，只想消除销售记录......这应该做到。

假设：只有回报才是负数单位和负数。

SELECT Sales.Account, Sales.Code, Sales.Item, Sales.Units, Sales.Amount 
FROM (SELECT Account, Code, Item, Units , Amount, Row_number() over (partition by Account, Code, Item, Units, Amount order by UniqSeq) RN
      FROM Fruit
      WHERE UNITS >= 0) Sales
LEFT JOIN (SELECT Account, Code, Item, Units , Amount, Row_number() over (partition by Account, Code, Item, Units, Amount order by UniqSeq) RN
           FROM Fruit
           WHERE UNITS < 0
             AND amount < 0) Returns
  on Sales.Account = Returns.Account
 and Sales.Code = Returns.Code
 and Sales.Item = Returns.Item
 and Sales.Units *-1 = Returns.Units
 and Sales.Amount *-1 = Returns.Amount
 and Sales.RN = Returns.RN
WHERE Returns.Account is null

和OrderID，或每行自动递增的ID ......

如果我假设oracle：

with  Fruit (uniqSeq, Account,    Code,      Item,   Units,   Amount) as 
(
select 1, 10325,      5972,  'Apple',  1,   .50 from dual union all
select 2, 10325,      5972,  'Apple',  -1,     -.50  from dual union all
select 3, 10325,      7231,  'Pear',   1,   .62  from dual union all
select 4, 10325,      7231,  'Pear',   1,   .62  from dual union all
select 5, 10431,      5972,   'Apple',  1,   .50  from dual )

SELECT Sales.Account, Sales.Code, Sales.Item, Sales.Units, Sales.Amount 
FROM (SELECT Account, Code, Item, Units , Amount, Row_number() over (partition by Account, Code, Item, Units, Amount order by UniqSeq) RN
      FROM Fruit
      WHERE UNITS >= 0) Sales
LEFT JOIN (SELECT Account, Code, Item, Units , Amount, Row_number() over (partition by Account, Code, Item, Units, Amount order by UniqSeq) RN
           FROM Fruit
           WHERE UNITS < 0
             AND amount < 0) Returns
  on Sales.Account = Returns.Account
 and Sales.Code = Returns.Code
 and Sales.Item = Returns.Item
 and Sales.Units *-1 = Returns.Units
 and Sales.Amount *-1 = Returns.Amount
 and Sales.RN = Returns.RN
WHERE Returns.Account is null

这里是带有连接的视图，显示“返回”派生表，消除了where子句......所以你可以看到为什么过滤对return.account为null的工作......

仅汇总特定订单项

2 个答案: