我的图片不会加载到imageview中,直到您将单元格从桌面滚动并重新打开,或转到另一个视图并返回到视图(重绘单元格)。
如何让它们正确加载?
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我的viewDidLoad中有这个:
tableView.delegate = self
tableView.dataSource = self
DispatchQueue.global(qos: .background).async {
self.getBusinesses()
DispatchQueue.main.async {
self.tableView.reloadData()
}
}
我调用函数在viewDidLoad中调用的.getBusinesses函数中下载图像:
func getBusinesses() -> Array<Business> {
var businessList = Array<Business>()
//let id = 1
let url = URL(string: "**example**")!
let data = try? Data(contentsOf: url as URL)
var isnil = false
if data == nil{
isnil = true
}
print("is nill is \(isnil)")
if(data == nil){
print("network error")
businessList = []
return businessList
}
else{
values = try! JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers) as! NSDictionary
}
let json = JSON(values)
var i = 0;
for (key, values) in json {
var businessReceived = json[key]
let newBusiness = Business(id: "18", forename: "", surname: "", email: "", password: "", business: true, level: 1, messageGroups: [], problems: [])
newBusiness.name = businessReceived["name"].stringValue
newBusiness.description = businessReceived["description"].stringValue
newBusiness.rating = Int(businessReceived["rating"].doubleValue)
newBusiness.category = businessReceived["category"].intValue
newBusiness.distance = Double(arc4random_uniform(198) + 1)
newBusiness.image_url = businessReceived["image"].stringValue
newBusiness.url = businessReceived["url"].stringValue
newBusiness.phone = businessReceived["phone"].stringValue
newBusiness.postcode = businessReceived["postcode"].stringValue
newBusiness.email = businessReceived["email"].stringValue
newBusiness.id = businessReceived["user_id"].stringValue
if(newBusiness.image_url == ""){
newBusiness.getImage()
}
else{
newBusiness.image = #imageLiteral(resourceName: "NoImage")
}
if(businessReceived["report"].intValue != 1){
businessList.append(newBusiness)
}
}
businesses = businessList
print(businesses.count)
holdBusinesses = businessList
return businessList
}
在业务对象中我有这个方法从url下载图像并将其存储在业务对象的图像属性中:
func getImage(){
if(self.image_url != ""){
print("runs imageeee")
var storage = FIRStorage.storage()
// This is equivalent to creating the full reference
let storagePath = "http://firebasestorage.googleapis.com\(self.image_url)"
var storageRef = storage.reference(forURL: storagePath)
// Download in memory with a maximum allowed size of 1MB (1 * 1024 * 1024 bytes)
storageRef.data(withMaxSize: 30 * 1024 * 1024) { data, error in
if let error = error {
// Uh-oh, an error occurred!
} else {
// Data for "images/island.jpg" is returned
self.image = UIImage(data: data!)!
print("returned image")
}
}
}
else{
self.image = #imageLiteral(resourceName: "NoImage")
}
}
然后我在这里的tableview中输出它:
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = self.tableView.dequeueReusableCell(withIdentifier: "Cell", for : indexPath) as! BusinessesViewCell
cell.businessImage.image = businesses[(indexPath as NSIndexPath).row].image
//.............
return cell
}
答案 0 :(得分:1)
self.image = UIImage(data: data!)!
应该成为
DispatchQueue.main.async {
self.image = UIImage(data: data!)!
}
内
storageRef.data(withMaxSize: 30 * 1024 * 1024) { data, error in
编辑:我最初的想法是下载逻辑在单元格内,现在我知道它不是。
每次到达
时,您都需要在tableView上调用reloadData() self.image = UIImage(data: data!)!
或更好地找出您刚更新的索引,然后调用
tableView.reloadRows:[IndexPath]
答案 1 :(得分:0)
您可以使用
cell.businessImage.setNeedsLayout()