Question

如何检查WHOLE字符串是否与正则表达式匹配？在Java中是方法String.matches(regex)

Answer 1

您要找的是range(of:options:range:locale:)然后您可以将范围（of：option :)的结果与整个比较字符串范围进行比较..

示例：

let phoneNumber = "(999) 555-1111" let wholeRange = phoneNumber.startIndex..<phoneNumber.endIndex if let match = phoneNumber.range(of: "\$?\\d{3}\$?\\s\\d{3}-\\d{4}", options: .regularExpression), wholeRange == match { print("Valid number") } else { print("Invalid number") } //Valid number

修改：您还可以使用NSPredicate并将字符串与其evaluate(with:)方法进行比较。

let pattern = "^\$?\\d{3}\$?\\s\\d{3}-\\d{4}$" let predicate = NSPredicate(format: "self MATCHES [c] %@", pattern) if predicate.evaluate(with: "(888) 555-1111") { print("Valid") } else { print("Invalid") }

Answer 2

您需要使用锚点^（字符串锚点的开头）和$（字符串锚点的结尾）和range(of:options:range:locale:)，并传递.regularExpression选项：< / p>

import Foundation

let phoneNumber = "123-456-789"
let result = phoneNumber.range(of: "^\\d{3}-\\d{3}-\\d{3}$", options: .regularExpression) != nil
print(result)

或者，您可以传递一系列选项[.regularExpression, .anchored]，其中.anchored仅将模式锚定在字符串的开头，您将能够省略^，但仍然需要$锚定在字符串结尾处：

let result = phoneNumber.range(of: "\\d{3}-\\d{3}-\\d{3}$", options: [.regularExpression, .anchored]) != nil

请参阅online Swift demo

此外，将NSPredicate与MATCHES一起使用是另一种选择：

根据ICU v3，左手表达式使用正则表达式比较等于右手表达式（有关详细信息，请参阅Regular Expressions的ICU用户指南）。

MATCHES实际上在字符串的开头和结尾都锚定了正则表达式匹配（注意这可能不适用于所有Swift 3版本）：< / p>

let pattern = "\\d{3}-\\d{3}-\\d{3}"
let predicate = NSPredicate(format: "self MATCHES [c] %@", pattern)
let result = predicate.evaluate(with: "123-456-789")

Answer 3

Swift extract regex matches

一点点编辑

import Foundation

func matches(for regex: String, in text: String) -> Bool {
    do {
        let regex = try NSRegularExpression(pattern: regex)
        let nsString = text as NSString
        let results = regex.matches(in: text, range: NSRange(location: 0, length: nsString.length))
        return !results.isEmpty
    } catch let error {
        print("invalid regex: \(error.localizedDescription)")
        return false
    }
}

上述链接的示例用法：

let string = "19320"
let matched = matches(for: "^[1-9]\\d*$", in: string)
print(matched) // will match

let string = "a19320"
let matched = matches(for: "^[1-9]\\d*$", in: string)
print(matched) // will not match

确保正则表达式与Swift正则表达式匹配整个字符串

3 个答案: