Question

我在数组中有卖家和买家信息，我需要检查id是否与数组中的卖家或买家ID匹配，然后我需要从数组中删除该对象。

这是数组：

[
  {
    "transactionId": null,
    "buyer": {
      "userId": "eu-central-1",
      "email": "pic@gmail.com",
      "firstName": "pic",
      "lastName": "1",
      "_id": "5902ca3ce201550655a7bbf8"
    },
    "seller": {
      "userId": "eu-central-2",
      "email": "pic2@gmail.com",
      "firstName": "pic",
      "lastName": "2",
      "_id": "5902ca3ce201550655a7bbf7"
    }
  }
]

我有用户ID eu-central-2 。我希望 expected output 为

[
  {
    "transactionId": null,
    "user": {
      "userId": "eu-central-1",
      "email": "pic@gmail.com",
      "firstName": "pic",
      "lastName": "1",
      "_id": "5902ca3ce201550655a7bbf8"
    } 
  }
]

我尝试了什么

  let data = results.filter(result=> seller.userId || buyer.userId == userId);

问题是删除部分并重命名用户。

Answer 1

var userId = 'eu-central-2';
var results = [
{
    "transactionId": null,
    "buyer": {
      "userId": "eu-central-1",
      "email": "pic@gmail.com",
      "firstName": "pic",
      "lastName": "1",
      "_id": "5902ca3ce201550655a7bbf8"
    },
    "seller": {
      "userId": "eu-central-2",
      "email": "pic2@gmail.com",
      "firstName": "pic",
      "lastName": "2",
      "_id": "5902ca3ce201550655a7bbf7"
    }
  }
];

如果要删除整个对象，请使用以下对象：

var data = results.filter(function(a) {
   if(a.buyer.userId == userId || a.seller.userId == userId) {
     return false;
   }
    return true;
});

或者，如果您要删除特定买方或卖方，请使用以下网址：

var data = results.filter(function(a) {
   if(a.buyer.userId == userId) {
     delete a.buyer;
   } else if(a.seller.userId == userId) {
     delete a.seller;
   }

   if(a.buyer) {
     a['user'] = a.buyer;
     delete a.buyer;
   } else if(a.seller) {
     a['user'] = a.seller;
     delete a.seller;
   }
    return true;
});

console.log(data);

Answer 2

我建议使用以下代码：

results.map(result => ({ 
        transactionId: result.transactionId, 
        user: [result.buyer, result.seller]
            [1-[result.buyer, result.seller].findIndex(user => user.userId === userId)]
    })).filter(result => result.user);

const results = [
  {
    "transactionId": null,
    "buyer": {
      "userId": "eu-central-1",
      "email": "pic@gmail.com",
      "firstName": "pic",
      "lastName": "1",
      "_id": "5902ca3ce201550655a7bbf8"
    },
    "seller": {
      "userId": "eu-central-2",
      "email": "pic2@gmail.com",
      "firstName": "pic",
      "lastName": "2",
      "_id": "5902ca3ce201550655a7bbf7"
    }
  },  {
    "transactionId": null,
    "buyer": {
      "userId": "eu-central-3",
      "email": "pic@gmail.com",
      "firstName": "pic",
      "lastName": "1",
      "_id": "5902ca3ce201550655a7bbf8"
    },
    "seller": {
      "userId": "eu-central-4",
      "email": "pic2@gmail.com",
      "firstName": "pic",
      "lastName": "2",
      "_id": "5902ca3ce201550655a7bbf7"
    }
  }
];

const userId = "eu-central-2";
const data = results.map(result => ({ 
        transactionId: result.transactionId, 
        user: [result.buyer, result.seller]
            [1-[result.buyer, result.seller].findIndex(user => user.userId === userId)]
    })).filter(result => result.user);

console.log(data);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

您需要对您的陈述更具体一点，因为javascript可能无法达到预期效果。如果我理解正确，您需要以下内容：

seller.userId === userId
OR
buyer.userId === userId

如果这是您想要的，那么used语句将无法工作，因为JS会将其视为：

seller.userId === true
OR
buyer.userId === userId

您可能需要做的只是提及userId两次，并使用这样的括号：(seller.userId == userId) || (buyer.userId == userId)

如何检查子对象是否包含id？

3 个答案: