Question

我想在javascript中找到一个重复的数字和它在对象数组中的名称。

我检查了相关问题但没有帮助找到确切的重复计数。如果有多个重复项，即使他们也不专注于找到它

我尝试了这个，它将在查找重复项时抛出消息。但是我想要重复计数并处理多个重复项的情况，每个名称的计数多次出现。

我的代码：

true

数组可能是这样的：

public static void main(String[] args) {
    while (each object in people[] != true) { // This obviously wouldn't
                                              // work but is the closest I
                                              // can get.
        object.loadPeople();
        object.moveElevator();
        object.unloadPeople();
    }
}

我想要一条消息，例如“name1重复发生2次”和“name2重复发生3次”

Answer 1

您可以只计算对象中的名称。

var array = [{ name: "name1", value: "value1" }, { name: "name2", value: "value2" }, { name: "name1", value: "value42" }, { name: "name2", value: "value52" }, { name: "name3", value: "value2" }, { name: "name2", value: "value2" }],
    count = Object.create(null);

array.forEach(function (o) {
    count[o.name] = (count[o.name] || 0) + 1;
});

Object.keys(count).forEach(function (k) {
    if (count[k] > 1) {
        console.log(k + ' is duplicate occuring ' + count[k] + ' times.');
    }
});

console.log(count);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

这将列出您的副本：

let array=[
{"name":"name1","value":"value1"},
{"name":"name2","value":"value2"},
{"name":"name1","value":"value42"},
{"name":"name2","value":"value52"},
{"name":"name3","value":"value2"},
{"name":"name2","value":"value2"}];

const counts = array.reduce((accum, current) => {
  accum[current.name] = (accum[current.name] || 0) + 1;
  return accum;
}, {});

Object.keys(counts)
  .filter(key => counts[key] > 1)
  .forEach(grp => console.log(`${grp} is duplicate occurring ${counts[grp]} times`));

在对象数组中查找重复数字及其名称

2 个答案: