Question

当用户点击某个项目并将其打印出来但是由于某种原因iid没有收到该event.y变量时，它意味着获取该树视图项的identify() ，也许？

import tkinter as tk
from tkinter import ttk

class App:
    def __init__(self):
        self.root = tk.Tk()
        self.tree = ttk.Treeview()
        self.tree.pack(side="top", fill="both")
        self.tree.bind("<<TreeviewSelect>>", self.tree_click_event)

        for i in range(10):
            self.tree.insert("", "end", text="Item %s" % i)

        self.root.mainloop()

    def tree_click_event(self, event):
        iid = self.tree.identify(event.x,event.y)
        print (iid)

if __name__ == "__main__":
    app = App()

单击树视图中的项目时，错误为：

TypeError: identify() missing 1 required positional argument: 'y'

在回复@TessellatingHeckler的评论时，根据链接对代码进行的编辑不会产生错误，但仍然无法打印出iid：

def tree_click_event(self, event):
    item = self.tree.identify('item', event.x,event.y)
    print (item)

感谢@CommonSense接受的答案摘要似乎我需要使用self.tree.bind（＆＃39;＆lt; 1＆gt;＆＃39;，self.tree_click_event）而不是treeviewselect来解决这个特殊问题，但感谢提供第二种做事方式

Answer 1

根据docs x, y坐标是

适用于KeyPress，KeyRelease，ButtonPress，ButtonRelease，Motion，Enter，Leave，Expose，Configure，Gravity和Reparent事件。

所以这里有一些解决方法针对您的问题进行一些调试打印（注意<<TreeviewSelect>>事件坐标！）：

try:
    import tkinter as tk
    import tkinter.ttk as ttk
except ImportError:
    import Tkinter as tk
    import ttk


class App:
    def __init__(self):
        self.root = tk.Tk()
        self.tree = ttk.Treeview()
        self.tree.pack(side="top", fill="both")
        self.tree.bind('<<TreeviewSelect>>', self.tree_click_event)
        self.tree.bind('<1>', self.on_click)
        for i in range(10):
            self.tree.insert("", "end", text="Item %s" % i)

        self.root.mainloop()


    def tree_click_event(self, event):
        real_coords = (self.tree.winfo_pointerx() - self.tree.winfo_rootx(),
                       self.tree.winfo_pointery() - self.tree.winfo_rooty())
        item = self.tree.identify('item', *real_coords)
        print('********** tree selection event **********')
        print('looks like this virtual event doesnt support event coordinates')
        print('event.x: %d, event.y: %d' % (event.x, event.y))
        print('real.x: %d, real.y: %d' % real_coords)
        print('clicked on', self.tree.item(item)['text'])
        print('******************************************\n')


    def on_click(self, event):
        item = self.tree.identify('item', event.x, event.y)
        print('********** tree mouse click event **********')
        print('clicked on', self.tree.item(item)['text'])
        print('event.x: %d, event.y: %d' % (event.x, event.y))
        print('******************************************\n')



if __name__ == "__main__":
    app = App()

输出：

Python tkinter treeview获取/返回所选项目的iid

1 个答案: