我试图绕过如何做一个正确的子查询,这对我没有意义,让我说我有两个表books
和chapters
:
图书
+----+------------------+----------+---------------------+
| id | name | author | last_great_chapters |
+----+------------------+----------+---------------------+
| 1 | some book title | john doe | 2 |
| 2 | foo novel title | some guy | 4 |
| 3 | other book title | lol man | 3 |
+----+------------------+----------+---------------------+
章节
+----+---------+----------------+
| id | book_id | chapter_number |
+----+---------+----------------+
| 1 | 1 | 1 |
| 2 | 1 | 3 |
| 3 | 1 | 4 |
| 4 | 1 | 5 |
| 5 | 2 | 1 |
| 6 | 2 | 2 |
| 7 | 2 | 3 |
| 8 | 2 | 4 |
| 9 | 2 | 5 |
| 10 | 3 | 1 |
| 11 | 3 | 2 |
| 12 | 3 | 3 |
| 13 | 3 | 4 |
| 14 | 3 | 5 |
+----+---------+----------------+
如何加入这两个表,并打印出" last_great_chapters"的行数(排序限制(last_great_chapters))。从每本书的书籍表列表?
答案 0 :(得分:0)
如果我理解正确,你想打印表格书和章节表中的last_great_chapters计数吗?
如果是,请尝试
select b.id, b.name, b.author , b.last_great_chapter, COUNT(c.chapter_number) as rownumbers FROM Books as b
LEFT JOIN Chapters AS C ON c.chapter_number = b.last_great_chapters
group by b.id, b.name, b.author , b.last_great_chapter