我正在尝试使用alpha beta修剪算法;我让程序正常运行。我需要弄清楚在选择alpha或beta值之前完成的搜索次数。我在计算值,但我不确定计数值是否正确。
int alpha_beta(const int level, const bool player, const Board &board, int alpha, int beta, Move &move) {
**static int count = 0;**
if (board.isGameOver() || level == 0) {
if (!board.isGameOver()) move = (board.legalMoves())[0];
return (getScore(board));
}
vector<Move> children = board.legalMoves();
tempBoard = board;
permutator(children.begin(), children.end());
//cout << count;
//getchar();
if (player == MAX) {
for (vector<Move>::iterator it = children.begin(); it != children.end(); it++) {
Board child = board.doMove(*it);
Move temp;
int score = alpha_beta(level - 1, !player, child, alpha, beta, temp);
if (score > alpha) {
alpha = score; // We have found a better best move
move = *it;
}
if (alpha >= beta) {
move = *it;
cout << alpha;
return alpha; // Beta Cut Off
cout << alpha;
}
count++;
}
**cout << "alpha count ="<<count;**
std::getchar();
return alpha; // This is our best move
}
else {
for (vector<Move>::iterator it = children.begin(); it != children.end(); it++) {
Board child = board.doMove(*it);
Move temp;
int score = alpha_beta(level - 1, !player, child, alpha, beta, temp);
if (score < beta) {
beta = score; // Opponent has found a better worse move
move = *it;
}
if (alpha >= beta) {
move = *it;
cout << beta;
return beta; // Alpha Cut Off
}
count++;
}
**cout <<" beta count ="<<count;**
std::getchar();
return beta; // This is the opponent's best move
}}
任何建议都会对搜索计数有所帮助。
答案 0 :(得分:1)
一个简单的想法可能是你应该首先实现Minimax算法,因为基本上,alpha beta修剪是Minimax的优化,因此如果你想获得在选择alpha或beta之前搜索的叶子总数,Minimax是也许是一个不错的选择。
在这种情况下,只要树到达离开节点
,就应该添加一个计数器if (board.isGameOver() || level == 0) {
count ++;
if (!board.isGameOver()) move = (board.legalMoves())[0];
return (getScore(board));
}