Question

我尝试使用PHP下载特定文件，如果我指定代码如下：

<?php

$file = '/home/myhome/public_html/myfolder/940903105955.txt';

if (file_exists($file)) {

     header('Content-Description: File Transfer');
     header('Content-Type: application/force-download');
     header('Content-Disposition: attachment; filename='.basename($file));
     header('Content-Transfer-Encoding: binary');
     header('Expires: 0');
     header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
     header('Pragma: public');
     header('Content-Length: ' . filesize($file));
     ob_clean();
     flush();
     readfile($file);
     exit;
}

?>

它有效，但请注意指定了文件名。

但是，如果我这样做：

    <?php

    $file_name = $_GET['file_name'];

    $file = '/home/myhome/public_html/myfolder/' + $file_name;

    if (file_exists($file)) {

    header('Content-Description: File Transfer');
     header('Content-Type: application/force-download');
     header('Content-Disposition: attachment; filename='.basename($file));
     header('Content-Transfer-Encoding: binary');
     header('Expires: 0');
     header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
     header('Pragma: public');
     header('Content-Length: ' . filesize($file));
     ob_clean();
     flush();
     readfile($file);
     exit;
    }

    ?>

它不起作用，为什么会这样？

这是处理下载到我电脑的java代码：

public static void saveFileFromUrlWithJavaIO(String fileName, String fileUrl)
    throws MalformedURLException, IOException {

    BufferedInputStream in = null;
    FileOutputStream fout = null;
    try {
        in = new BufferedInputStream(new URL(fileUrl).openStream());
        fout = new FileOutputStream(fileName);

        byte data[] = new byte[1024];
        int count;

        while ((count = in.read(data, 0, 1024)) != -1) {

            fout.write(data, 0, count);
            System.out.print(data);
        }

    } finally {

        if (in != null)
        in.close();
        if (fout != null)
        fout.close();
}

这就是我调用函数的方式：

private void btn_downloadActionPerformed(java.awt.event.ActionEvent evt) {                                             
    // TODO add your handling code here:       
    String url = "http://myurl.com/download_resubmission_file.php?file_name="+ "940903105955.txt";

    try {
       saveFileFromUrlWithJavaIO(path_to_save_file, url);
    } catch (IOException ex) {
        Logger.getLogger(InsuranceMain.class.getName()).log(Level.SEVERE, null, ex);
    }
}

Answer 1

尝试更改此行：

$file = '/home/myhome/public_html/myfolder/' + $file_name;

为：

$file = '/home/myhome/public_html/myfolder/' . $file_name;

在PHP文件中。

使用PHP下载特定文件

1 个答案: