Question

我不断收到错误代码400：缺少参数 我认为问题是我在

中发送数据的格式

API DOC：http://middleware.idxbroker.com/docs/api/methods/index.html#api-Leads-putLead

我认为呼叫所需的数据是名字，姓氏和电子邮件，我是否需要将其他字段作为nil发送，还是可以将其留空？

API调用

/// Send Lead to IDX Broker
///
/// - Parameter lead: new Lead data fields
/// - Returns: configs for URL Session
class func putLead(lead: String) -> URLRequest {

    let urlString = "https://api.idxbroker.com/leads/lead"
    let url = NSURL(string: urlString)

    var downloadTask = URLRequest(url: (url as URL?)!, cachePolicy: URLRequest.CachePolicy.reloadIgnoringCacheData, timeoutInterval: 20)
    /******************** Add Headers required for API CALL *************************************/
    downloadTask.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
    downloadTask.setValue(APICalls.getAccessKey(), forHTTPHeaderField: "accesskey")
    downloadTask.setValue("json", forHTTPHeaderField: "outputtype")
    downloadTask.httpMethod = "PUT"
    downloadTask.httpBody = lead.data(using: .utf8)
    /******************** End Headers required for API CALL *************************************/

    return downloadTask
}

发送给函数的数据

 /// Create lead from text fields
    let postString = "lead(firstName=\(String(describing: firstName.text!))&lastName=\(String(describing: lastName.text!))&=email=\(String(describing: Email.text!)))"

    /// URL Encoding for put API
    let escapedString = postString.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed)
    print(escapedString!)
    print(escapedString?.data(using: .utf8) ?? "Error")

    /// API Call with passing json String
    let downloadTask = APICalls.putLead(lead: escapedString!)


    URLSession.shared.dataTask(with: downloadTask, completionHandler: {(data, response, error) -> Void in

        /// Status Returned from API CALL
        if let httpResponse = response as? HTTPURLResponse {
            print("statusCode: \(httpResponse.statusCode)")
        }


    }).resume()
    /******** End URL Session **********/

Answer 1

400表示API没有开启，或者您传递的参数更多。如果API收到firstName，那么它会回复一个错误，指出没有收到lastName。如果第一个和最后一个通过，那么它将回复未收到的电子邮件。

测试你的代码当我没有在postString中使用lead（）时，我能够获得预期的字符串。

swift PUT API调用缺少的参数

1 个答案: