当数组中的键不同时，过滤对象中的值

Question

来自获取请求的回复：

[
    {
    id: 234,
    resturant_name : "dish",
    cusions : {1:"italian", 2 : "indian", 3: "foo"},
    address : NYI

    },
    {
        id: 235,
        resturant_name : "kebab",
        cusions : {1:"china", 2 : "indian", 3: "american"},
        address : NYI

    },
    {
        id: 236,
        resturant_name : "itrup",
        cusions : {1:"italian", 2: "american"},
        address : NYI

    }
]

我想过滤一个具有“美国”类型的cusions数组的数组，从上面的对象中我期待回应

   {
        id: 235,
        resturant_name : "kebab",
        cusions : {1:"china", 2 : "indian", 3: "american"},
        address : NYI

    },
    {
        id: 236,
        resturant_name : "itrup",
        cusions : {1:"italian", 2: "american"},
        address : NYI

    }

过滤后

^^^

Answer 1

您可以将Array#filter与Object.keys和Array#some结合使用来检查所需的cuisine。

var data = [{ id: 234, restaurant: "dish", cuisines: { 1: "italian", 2: "indian", 3: "foo" }, address: "NYI" }, { id: 235, restaurant: "kebab", cuisines: { 1: "china", 2: "indian", 3: "american" }, address: "NYI" }, { id: 236, restaurant: "itrup", cuisines: { 1: "italian", 2: "american" }, address: "NYI" }],
    cuisine = 'american',
    result = data.filter(function (a) {
        return Object.keys(a.cuisines).some(function (k) {
            return a.cuisines[k] === cuisine;
        });
    });

console.log(result);

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ES6

var data = [{ id: 234, restaurant: "dish", cuisines: { 1: "italian", 2: "indian", 3: "foo" }, address: "NYI" }, { id: 235, restaurant: "kebab", cuisines: { 1: "china", 2: "indian", 3: "american" }, address: "NYI" }, { id: 236, restaurant: "itrup", cuisines: { 1: "italian", 2: "american" }, address: "NYI" }],
    cuisine = 'american',
    result = data.filter(a => Object.values(a.cuisines).includes(cuisine));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

其中一种方法：

var arr = [
    {
    id: 234,
    resturant_name : "dish",
    cusions : {1:"italian", 2 : "indian", 3: "foo"},
    address : 'NYI'

    },
    {
        id: 235,
        resturant_name : "kebab",
        cusions : {1:"china", 2 : "indian", 3: "american"},
        address : 'NYI'

    },
    {
        id: 236,
        resturant_name : "itrup",
        cusions : {1:"italian", 2: "american"},
        address : 'NYI'

    }
];

var res = arr.filter(x=> {
	return JSON.stringify(x.cusions).indexOf('american') >=0;
});

console.log(res);