SQL查找子查询

Question

我有一张工资表，我必须找到零的平均值与零之间的差异，所以这是我的查询

SELECT ((SELECT REPLACE(Salary, '0', '') FROM TEST) - (SELECT ROUND(SUM(Salary)/COUNT(*)) FROM Test)) FROM Test

不幸的是我的查询无效。 示例5工资：5049,7000,2000,3900
我必须找到5049,7000,2000,3900和549,7,2,39

的平均值

Answer 1

试试这个：

SELECT a.without, a.with, a.with - a.without
FROM(
  SELECT AVG(CAST(REPLACE(Salary, '0', '') AS INT)) AS 'without', AVG(salary) 
  as 'with'
  FROM test) a