Question

我有一个Xcode应用程序，我正在更新到最新的iOS。我现在注意到在构建时我有以下错误/警告：

/ConfViewController.m:198:46：＆＃39; sendSynchronousRequest：returningResponse：error：＆＃39;不推荐使用：首先在iOS 9.0中弃用 - 使用[NSURLSession dataTaskWithRequest：completionHandler：]（参见NSURLSession.h

根据我的阅读，我应该开始使用＆＃34; NSURLSession＆＃34;但我如何使用＆＃34; NSURLSession＆＃34;在我的代码中，还是我看错了？

我的代码：

NSString *deviceName = [[UIDevice currentDevice]name];
        NSString *post =[[NSString alloc] initWithFormat:@"devicename=%@",deviceName];
        NSLog(@"PostData: %@",post);

        NSURL *url=[NSURL URLWithString:@"http://www.mydomain/sysscripts/conf/devicelookup17.php"];


        NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

        NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];

        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
        [request setURL:url];
        [request setHTTPMethod:@"POST"];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:postData];

        NSError *error = [[NSError alloc] init];
        NSHTTPURLResponse *response = nil;

//The ERROR point
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

        //NSLog(@"Response code: %ld", (long)[response statusCode]);
        if ([response statusCode] >=200 && [response statusCode] <300)
        {
            NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
            NSLog(@"Response ==> %@", responseData);

            SBJsonParser *jsonParser = [SBJsonParser new];
            NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:responseData error:nil];
           // NSLog(@"%@",jsonData);

           // NSInteger success = [(NSNumber *) [jsonData objectForKey:@"success"] integerValue];
            NSInteger roomid = [(NSNumber *) [jsonData objectForKey:@"roomid"] integerValue];
           // NSLog(@"%ld",(long)success);
            //NSLog(@"%ld",(long)roomid);
            NSString *RoomID =  [NSString  stringWithFormat:@"%ld",(long)roomid];
           // NSLog(@"%@", RoomID);

            NSString *firstString = @"http://www.mydomain/apps/conf/lon/dt/devices/ /template17.php";
           // NSLog(@"%@", firstString);

            NSString *roomID = RoomID;
           // NSLog(@"%@", roomID);

            NSString *newString = [firstString stringByReplacingOccurrencesOfString:@" " withString:roomID];
          //  NSLog(@"%@", newString);

            NSURL *url2 = [NSURL URLWithString: newString];
            NSLog(@"%@", url2);

            NSURLRequest *request2 = [NSURLRequest requestWithURL:url2];


           // ConfViewController *navex =[[ConfViewController alloc] initWithNibName:nil bundle:nil];
            //[self presentViewController:navex animated:YES completion:NULL];
            [webView loadRequest:request2];



        }

非常感谢你的时间。

Answer 1

替换

NSData *urlData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

与

[[[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData * data, NSURLResponse * response, NSError * error) {


}] resume];

将整个代码放在完成块中的sendSynchronousRequest行之后（括号之间）。

替换

if ([response statusCode] >=200 && [response statusCode] <300)

带

NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;
NSInteger statusCode = httpResponse.statusCode;
if (statusCode >= 200 && statusCode < 300)

将urlData替换为data。

删除

NSError *error = [[NSError alloc] init];
NSHTTPURLResponse *response = nil;

不推荐使用sendSynchronousRequest：returningResponse

1 个答案: