Question

如何将这些字符串转换为日期格式并进行相应排序....请

2010-11-08 18:58:50.0_getCreated_10180  
2010-11-09 17:49:42.0_getCreated_10180  
2010-11-09 17:49:42.0_getCreated_10180  
2010-11-24 19:44:51.0_getCreated_10180  
2010-11-09 13:54:46.0_getCreated_10180  
2010-11-23 20:06:29.0_getCreated_10180  
2010-11-23 20:06:04.0_getCreated_10180  
2010-11-15 17:51:37.0_getCreated_10180

提前致谢，约瑟夫

Answer 1

如果你有一个字符串，那么就做。

// first create an array by splitting the string at the newlines
var list = dateString.split('\n'); 
list = list
    .map( // for each element in the list (each date)
        function(val,idx){
            // use the first part(before the dot(.)), replace the - with spaces and convert to date
            return new Date(val.split('.')[0].replace(/-/g,' '));
    })
    .sort(); // at the end sort the results.

示例http://www.jsfiddle.net/gaby/rfGv8/

我们需要为每个日期（行）做什么

2010-11-08 18:58:50 ~~.0_getCreated_10180~~ （删除。之后的部分）
用val.split('.')[0]

完成

然后用空格替换 - 使其看起来像2010 11 08 18:58:50，这是Date构造函数可接受的日期格式。
用val.split('.')[0].replace(/-/g,' ')

完成

然后将其作为参数传递给Date的构造函数以创建Date对象
用new Date(val.split('.')[0].replace(/-/g,' '))

完成

将上述内容应用于所有元素并获取新数组后，使用.sort()方法按升序排序数组。

Answer 2

请提供以下代码。 getDateSort函数返回排序日期

 <script language="javascript" type="text/javascript">

            function getDateSort() {


                dateArray = new Array('2010-11-08 18:58:50', '2010-11-09 17:49:42',
    '2010-11-09 17:49:42', '2010-11-15 17:51:37', '2010-11-23 20:06:04', '2010-11-09 13:54:46', '2010-11-23 20:06:29', '2010-11-24 19:44:51');
                dateArray.sort(dmyOrdA);
                alert('Ascending : ' + dateArray + '');
                return false;
            }


            var dateRE = /^(\d{2})[\/\- ](\d{2})[\/\- ](\d{4})/;
            function dmyOrdA(a, b) {
                a = a.replace(dateRE, "$3$2$1");
                b = b.replace(dateRE, "$3$2$1");
                if (a > b) return 1;
                if (a < b) return -1;
                return 0;
            }
            function dmyOrdD(a, b) {
                a = a.replace(dateRE, "$3$2$1");
                b = b.replace(dateRE, "$3$2$1");
                if (a > b) return -1;
                if (a < b) return 1;
                return 0;
            }
            function mdyOrdA(a, b) {
                a = a.replace(dateRE, "$3$1$2");
                b = b.replace(dateRE, "$3$1$2");
                if (a > b) return 1;
                if (a < b) return -1;
                return 0;
            }
            function mdyOrdD(a, b) {
                a = a.replace(dateRE, "$3$1$2");
                b = b.replace(dateRE, "$3$1$2");
                if (a > b) return -1;
                if (a < b) return 1;
                return 0;
            }

        </script>

通过将字符串转换为日期格式来进行Javascript日期排序

2 个答案: