如果在java中2个句子相等，如何比较两个句子并检索一个单词或几个单词

Question

我在变量String语句中有一个输入句子，想要与java中的一组String [] sentence2进行比较，如下所示

String sentence = "I am fine today";
String[] sentence2= {"how are %s to day", I am %s today","thank %s for you answer"}

此问题的输出结果为真实条件（匹配）并检索单词＆＃34;罚款＆＃34;。 如果输入改变如下：String sen =我今天很开心，输出结果为真实条件（匹配）并检索单词＆＃34;罚款＆＃34;

我有一个函数并使用split将句子分成单词并与数组单词

进行比较

 if (similarity(sentence,sentence2)>2) {
     String a = getkata(sentence, sentence2);
    ..
    }
    public static int similarity(String a, String b) {
            int count = 0;
            String[] words = a.split(" ");
           // String[] words2=b.split(" ");
            for (int i=0; i < words.length; i++){
                if(b.contains(words[i])) {
                    System.out.println(i);
                    count=count+1;
                }

            }
            return count;
        }
public static String getkata(String a, String b){
        String hasil="";
        String[] kata = a.split(" ");
        String[] cari = b.split(" ");
        for (int i=0; i< kata.length; i++){
            if(cari[i].contains("%s")){
                hasil = kata[i];
            }
        }
        return hasil;
}

这段代码工作，但我希望代码直接比较两个句子而不分成单词

Answer 1

如果您可以将%s替换为(.*?)，那么您可以解决90％的问题，例如可以使用匹配进行检查：

public static void main(String[] args) {
    String sen = "I am fine today";
    String[] sen2 = {"how are (.*?) to day", "I am (.*?) today", "thank (.*?) for your answer"};
    for (String s : sen2) {
        if (sen.matches(s)) {
            System.out.print("Matche : ");
            System.out.println(sen);
        }else{
            System.out.println("Not Matche");
        }
    }
}

这将告诉你：

Not Matche
Matche : I am fine today
Not Matche

修改

  

我想要一个布尔值为真的答案并检索％s字

在这种情况下，您可以使用Pattern和Matches作为例子：

public static void main(String[] args) {
    String sen = "I am fine today";
    String[] sen2 = {"how are (.*?) to day", "I am (.*?) today", "thank (.*?) for your answer"};
    Pattern pattern;
    Matcher matcher;
    for (String s : sen2) {
        pattern = Pattern.compile(s);
        matcher = pattern.matcher(sen);
        if (matcher.find()) {
            System.out.println("Yes found : " + matcher.group(1));
        }
    }
}

<强>输出

Yes found : fine

Answer 2

这应该有效：

    for (String s: sen2) {
        Pattern pat = Pattern.compile(s.replace("%s", "(.*)"));
        Matcher matcher = pat.matcher(sen);
        if (matcher.matches()) {
            System.out.println(matcher.group(1));
        }
    }