Question

我在我的php文件的同一文件夹中运行我的文件，并且我还使用Apache的管理员帐户登录。这是我的代码： <?php exec("testbat.bat"); ?>

Answer 1

创建一个文件并将其另存为filename.bat

这是一个例子

批处理文件名是test.bat

@Override
public void doPost(HttpServletRequest request, HttpServletResponse response)  
    throws ServletException, IOException {  

    response.setContentType("text/html");  
    PrintWriter out = response.getWriter();  

    String email = request.getParameter("email");  
    String password = request.getParameter("password");  

    if (Login.validate(email, password)) {  
        RequestDispatcher rd = request.getRequestDispatcher("servlet2");  
        rd.forward(request,response);  
    }  
    else {  
        out.print("Sorry username or password error");  
        RequestDispatcher rd = request.getRequestDispatcher("index.html");  
        rd.include(request,response);  
    }           
    out.close();  
}

之后从php文件“executeme.php”

调用它

public static boolean validate(String email,String password){  
    boolean status=false;  
    try {  
        Class.forName("com.mysql.jdbc.Driver");
        String conStr = "jdbc:mysql://localhost:3306/virtuoso?user=root&password=";
        Connection con = DriverManager.getConnection(conStr); 

        String sql = "SELECT * FROM tutor WHERE email=? and password=?";
        PreparedStatement ps = con.prepareStatement(sql);  
        ps.setString(1,email);  
        ps.setString(2,password);  

        ResultSet rs = ps.executeQuery();  
        status = rs.next();  
    } catch (ClassNotFoundException | SQLException e) {
        //empty
    }  
    return status;  
}

无法在PHP wamp中执行.bat文件

1 个答案: