php webservice

Question

在我的Android应用中，我希望每个用户都有唯一的ID。我已经完成了$ uuid = uniqid（''，true）;这个功能在PHP中。它将为每个用户生成唯一的ID，它将存储在数据库中。现在我想在下一页上获得此ID。我会用session。

Inserdata.php

 public function StoreSocialInfo($firstname, $lastname, $email)
{
    $uuid = uniqid('', true);

    $_SESSION["newsession"] = $uuid;

    $stmt = $this->conn->prepare("INSERT INTO ibeInsert(unique_id,firstname,lastname,email) VALUES(?,?,?,?)");
    $stmt->bind_param("ssss", $uuid,$firstname,$lastname,$email);
    $result = $stmt->execute();
    $stmt->close();


    if($result)
    {
        $stmt = $this->conn->prepare("SELECT firstname,lastname,email,unique_id FROM ibeInsert WHERE email = ?");
        $stmt->bind_param("s",$email);
        $stmt->execute();
        $stmt->bind_result($token2,$token3,$token4,$token5);
        while( $stmt->fetch() )
        {
            $user["firstname"]=$token2;
            $user["lastname"]=$token3;
            $user["email"]=$token4;
            $user["unique_id"]=$token5;
        }
        $stmt->close();
        return $user;
    }
    else
    {
        return false;
    }
}

使用此代码，它将成功存储在数据库中。现在从另一个页面上的会话中获取此值。在此代码中，我没有在浏览器中获取会话值，但我将进入邮递员。

getdata.php
 <?php

  session_start();
  error_reporting(E_ALL);
  ini_set('display_errors', 1);

 $dbhost = 'localhost';
 $dbuser = '***';
 $dbpass = '***';
 $conn = mysql_connect($dbhost, $dbuser, $dbpass);
 if(! $conn )
 {
   die('Could not connect: ' . mysql_error());
 }

 $uuid = $_SESSION['newsession'];
 var_dump($uuid);


$sql = "SELECT * FROM ibeInsert where unique_id = $uuid ";

mysql_select_db('****');
$retval = mysql_query( $sql, $conn );

$response = array();

if(! $retval )
{
  die('Could not get data: ' . mysql_error());
}
 while($row = mysql_fetch_assoc($retval))
{
     array_push($response,array("status"=>$row["status"], 
   "unique_id"=>$row["unique_id"],"elite_id"=>$row["elite_id"]));
}
 echo json_encode($response);


mysql_close($conn);
 ?>

here I will get session value on another page in postman here I will get null response in web browser