我在使用用户定义的函数将单个单元格字符串分解为多个值时遇到问题,然后以索引/匹配方式匹配每个值,返回单个单元格,其中包含用逗号分隔的匹配值的字符串
示例:
Roles Names Role Name
role1/role2 name1,name2 role1 name1
role1 name1 role2 name2
role2/role3 name2,name3 role3 name3
role1/role4 name1,name4 role4 name4
role3/role5 name3,name5 role5 name5
我想获得一个从Roles,Role和Name列生成“names”列的函数。
到目前为止,这是我的VBA代码:
Public Function RoleToName(role, roles_rng, names_rng) As String
Dim result As String
Dim s As Variant
For Each s In Split(role, "/")
???
Next s
End Function
感谢。
答案 0 :(得分:2)
Public Function RoleToName(role, roles_rng, names_rng) As String
Dim result As String
Dim s As Variant, m, sep As String
For Each s In Split(role, "/")
'Trim each value in case of extra spaces...
m = Application.Match(Trim(s), roles_rng, 0)
If Not IsError(m) Then
result = result & sep & names_rng.Cells(m).Value
Else
result = result & sep & "??" '<< role not found...
End If
sep = ","
Next s
RoleToName = result
End Function
答案 1 :(得分:0)
试一试,
Function udf_CollateNames(roles As String, tbl As Range, _
Optional roleSplit As String = "/", _
Optional delim As String = ",")
Dim v As Long, vVALs As Variant
vVALs = Split(roles, roleSplit)
For v = LBound(vVALs) To UBound(vVALs)
If Not IsError(Application.Match(Trim(vVALs(v)), tbl.Columns(1), 0)) Then _
udf_CollateNames = udf_CollateNames & delim & Application.VLookup(Trim(vVALs(v)), tbl, 2, False)
Next v
udf_CollateNames = Mid(udf_CollateNames, Len(delim) + 1)
End Function