如何在Python 3中重复删除列表中的项目?对于我的代码的第一个项目,但如果我尝试应用再次删除项目的方法,它会生成TypeError
。这是我正在使用的代码:
from random import choice
class Black_jack_deck(object):
def __init__(self, full_deck=(([str(i) for i in range(2,11)]+["A","J","Q","K"])*4*6)): #a deck of 312 cards containing 6* 52 french cards
self.full_deck = full_deck
def draw(self, draw=True):
self.draw = choice(self.full_deck) #I use choice to simulate the dealer drawing a card from the top of a mixed card staple
return self.draw
self.full_deck = (self.full_deck).remove(self.draw)
deck = Black_jack_deck()
我尝试第二次调用deck.draw()
时产生的错误如下所示:
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
deck.draw()
TypeError: 'str' object is not callable
注意:即使没有choice()
函数,例如在混合pop()
上使用full_deck
,也会发生同样的错误。
答案 0 :(得分:1)
您使用卡片覆盖了Black_jack_deck.draw()
方法。因此,deck.draw()
的错误是'str' object
和is not callable
。
这是一个较短的版本。你需要记住鞋子里的卡片吗?我删除了draw()
的布尔参数,因为我不知道它为什么存在。
In [94]: class CardShoe(object):
...: def __init__(self, num_decks=6):
...: self.cards = list('A23456789JQK' * 4 * num_decks)
...: random.shuffle(self.cards)
...:
...: def draw(self):
...: self.last_card_drawn = self.cards.pop()
...: return self.last_card_drawn
...:
In [95]: shoe = CardShoe()
In [96]: shoe.draw()
Out[96]: '2'
In [97]: shoe.draw()
Out[97]: '8'