Question

我想要的是，解决一个新的活动是考虑到名称而不是位置，例如这里我有两个名字“Ciclismo”和“Correr”，这里代码：

public class MainActivity extends Activity {

ListView lista;
ArrayList<Datos> arraydatos = new ArrayList<Datos>();
Datos datos;
adapterdatos adapter = new adapterdatos(this, arraydatos);

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    lista = (ListView) findViewById(R.id.listView_lista);


    datos = new Datos(getResources().getDrawable(R.drawable.ciclistapng), "Ciclismo", "Imagen de tipo PNG");
    arraydatos.add(datos);
    datos = new Datos(getResources().getDrawable(R.drawable.corredor), "Correr", "Imagen de tipo PNG");
    arraydatos.add(datos);


    lista.setAdapter(adapter);
    registerForContextMenu(lista);
}
@Override
public void onCreateContextMenu (ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    MainActivity.super.onCreateContextMenu(menu, v, menuInfo);
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.main_context_menu, menu);
    lista.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

            switch (position) {
                case 0:
                    Intent ci = new Intent(getApplicationContext(), ciclismo.class);
                    startActivity(ci);
                    Toast.makeText(getApplicationContext(), "Ciclismo", Toast.LENGTH_SHORT).show();
                    break;

                case 1:
                    Toast.makeText(getApplicationContext(), "Correr", Toast.LENGTH_SHORT).show();
                    break;
            }
        }
    });
}
@Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
    switch (item.getItemId()) {
        case R.id.delete_id:
            arraydatos.remove(info.position);
            adapter.notifyDataSetChanged();
            Toast.makeText(getApplicationContext(),"Eliminado", Toast.LENGTH_SHORT).show();
            return true;

        case R.id.añadir_id:
            arraydatos.add(datos);
            adapter.notifyDataSetChanged();
            Toast.makeText(getApplicationContext(),"Añadido", Toast.LENGTH_SHORT).show();
            return true;
        default:
            return MainActivity.super.onContextItemSelected(item);
    }
}
}

我希望它不是因为它的位置而是它在listview中的名称。谢谢你，原谅我的英语。

Answer 1

我所理解的是，当在ListView中单击某个项目时，您希望通过名称而非位置来获取它。纠正我，如果错了。 ListView点击通常是通过位置获得的，但您可以通过在listview项目中设置标记来获取视图名称。

如何打开不具有位置但具有名称的新活动？

1 个答案: