Question

尝试编写一个脚本来玩猜谜游戏。脚本应该生成一个数字并请求用户猜测。然后，该脚本将比较用户输入的数字与生成的数字，它应确保游戏继续，直到用户请求怜悯或正确猜测数字。它应该向用户提供更高或更低的提示以帮助他们。一旦获胜条件之一发生，用户应该以某种方式表示祝贺，然后脚本应该结束。如果用户请求怜悯，它应该回显一个不同的短语。

#!/bin/sh

number="$(( ( RANDOM % 100 )  + 1 ))"

echo "Guess a number between 1 and 100, or say 'mercy'"
read answer
until [[ $answer -eq $number || $answer -eq "mercy" ]]
do
    if [ $answer -lt $number ]
    then
        echo "Guess higher"
        read answer
    else
        echo "Guess lower"
        read answer
    fi
done

if [ $answer -eq "mercy" ]
then
    echo "You are a quitter"
else
    echo "CONGRATS"
fi

每次你猜对了，或者只是说出怜悯和错误代码：line 19: [: mercy: integer expression expected

Answer 1

您正在使用-eq进行字符串比较; -eq用于整数比较 - 您需要使用=或==。这就是你得到错误的原因。

此外，/bin/sh不一定是bash。因此，请将#!/bin/bash用作shebang。

#!/bin/bash

number="$(((RANDOM % 100) + 1))"

echo "Guess a number between 1 and 100, or say 'mercy'"
read answer
until [[ $answer -eq $number || $answer == "mercy" ]]
do
    if [[ $answer -lt $number ]]
    then
        echo "Guess higher"
        read answer
    else
        echo "Guess lower"
        read answer
    fi
done

if [[ $answer == "mercy" ]]
then
    echo "You are a quitter"
else
    echo "CONGRATS"
fi

除非您打算将此脚本移植到其他POSIX shell，否则我建议您使用[[ .. ]]而不是[ .. ]。见What is the difference between test, [ and [[ ?

Answer 2

我会使用类似的东西：

#!/bin/bash

number="$(( ( RANDOM % 100 )  + 1 ))"

steps=0
while :
do
    read -r -p "Guess a number between 1 and 100, or say 'mercy'> " answer
    case "${answer,,}" in
        [0-9]|[0-9][0-9]) let steps++ ;;
        mercy) echo "Quitter after $steps steps" ; exit 0;;
        *) echo "Don't understand the $answer" ; continue ;;
    esac

    case 1 in
    $(( answer < number )) ) echo "Guess higher" ;;
    $(( answer > number )) ) echo "Guess lower" ;;
    $(( answer == number )) ) echo "winner in $steps steps" ; exit ;;
    esac
done

bash中来自[[$ answer -eq“mercy”]]的“整数表达式”

2 个答案: