Django:" Model"匹配查询不存在

时间:2017-04-26 14:38:45

标签: python mysql django

为了记录,我已经在这个网站上搜索了类似的答案,但是我仍然在试图解决这个问题时仍然撞墙。

我使用的是Django版本1.10,我正在运行MySQL作为数据库引擎。我希望在将信息保存到我的数据库时(通过我的视图)同时更新相关模型中的OneToOneField,但会抛出错误" IndividualEmp"匹配查询不存在。

以下是模型:

class IndividualEmp(models.Model):
name = models.CharField(max_length = 100, db_column = 'name', primary_key = True)
department = models.CharField(db_column='department', max_length=30, blank=True, null=True)
emp_type = models.CharField(db_column='emp_Type', max_length=15, blank=True, null=True)

class Meta:
    managed = False
    db_table = 'individual_emp'
    app_label = 'users'

class IndividualDetails(models.Model):
d_name = models.OneToOneField(IndividualEmp, models.DO_NOTHING, 
                              db_column = 'd_name', primary_key = True)
gender = models.CharField(max_length=1, blank=True, null=True)
email = models.CharField(max_length=20, blank=True, null=True)
phone = models.CharField(max_length=9, blank=True, null=True)

class Meta:
    managed = False
    db_table = 'individual_details'
    app_label = 'users'

这是我的views.py文件:

from users.forms import Register
from users.models import (Attendee, IndividualDetails, IndividualEmp)

# Create your views here.

def signup(request):
form = Register(request.POST)
if request.method == 'POST':
    if form.is_valid():

        obj = Attendee()
        obj_1 = IndividualDetails()
        obj_2 = IndividualEmp()

        obj.attendee_ID = form.cleaned_data['attendee_ID']            
        obj_1.name = form.cleaned_data['name']
        obj_1.department = form.cleaned_data['department']
        obj_1.emp_type = form.cleaned_data['emp_type']
        obj_2.gender = form.cleaned_data['gender']
        obj_2.email = form.cleaned_data['email']

        obj_3 = IndividualEmp.objects.get(name = 'name')

        request.d_name.individualdetails.individualemp = obj_3
        request.d_name.individualdetails.save()

        obj.save()
        obj_1.save()
        obj_2.save()

        return HttpResponseRedirect('users/signup')

else:
    form = Register()

return render(request, 'users/signup.html', {'form': form}))

这是追溯:

Environment:


Request Method: POST
Request URL: http://127.0.0.1:8000/users/signup/

Django Version: 1.10.6
Python Version: 2.7.11
Installed Applications:
['django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'users']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']

Traceback:

File "C:\Users\Stone\Anaconda2\lib\site-packages\django\core\handlers\exception.py" in inner
  42.             response = get_response(request)

File "C:\Users\Stone\Anaconda2\lib\site-packages\django\core\handlers\base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "C:\Users\Stone\Anaconda2\lib\site-packages\django\core\handlers\base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "C:\Program Files\virtualenvs\env1\fireball\users\views.py" in signup
  25.             obj_3 = IndividualEmp.objects.get(name = 'name')

File "C:\Users\Stone\Anaconda2\lib\site-packages\django\db\models\manager.py" in manager_method
  85.                 return getattr(self.get_queryset(), name)(*args, **kwargs)

File "C:\Users\Stone\Anaconda2\lib\site-packages\django\db\models\query.py" in get
  385.                 self.model._meta.object_name

Exception Type: DoesNotExist at /users/signup/
Exception Value: IndividualEmp matching query does not exist.

同样,我想做的就是在IndividualEmp" name"中输入一个字段,并将相同的条目传递给IndividualDetails" d_name"并将其保存到我的数据库。如果我没有发布足够的信息,请原谅我。

1 个答案:

答案 0 :(得分:0)

 obj_3 = IndividualEmp.objects.get(name = 'name')

当您使用“get”方法时,django期望在数据库中只有一个具有该名称的记录。如果该名称不止一个或根本没有,则会抛出异常。

https://docs.djangoproject.com/en/1.11/topics/db/queries/#retrieving-a-single-object-with-get