Question

我发现很多关于使用$elemMatch，$set，$in等更新MongoDB（3.4）文档的帖子。但我需要的是更新所有{{1} }此嵌套单个文档中的animal_rules为type 。

any_rule2

我尝试了{ "_id": "id_1", "animals": { "a_random_very_long_id1": { "animal_actions": [{ "type": "any_action1", "additional_things": [ "90000201" ] }], "animal_rules": [{ "type": "any_rule1", "unrelated_field": 15 }, { "type": "any_rule2", "important_value": 60 }], "_id": "a_random_very_long_id1" }, "a_random_very_long_id2": { "animal_actions": [{ "type": "any_action2", "additional_things": [ "10567808" ] }], "animal_rules": [{ "type": "any_rule2", "important_value": 50 }, { "type": "any_rule3", "other_unrelated_field": { "type": "xx" } } ], "_id": "a_random_very_long_id2" } } }之类的内容，但我甚至无法获取结果。

Answer 1

我找不到任何单行程来完成这项任务，最后我想出了这个Javascript函数：

var x = db.general.findOne({"_id" : "_id1"});
for (key in x.animals) {
    rules = x.animals[key].animal_rules;
    rules.forEach(function (rule) {
        type = rule.type;
        if (type === 'any_rule2') {
            theValue = rule.important_value;
            rule.from = NumberInt(theValue);
            rule.to = NumberInt(theValue);
            delete rule.important_value;
        }
    });
printjson(x);
db.general.save(x);
}

希望它能为某人服务:)

MongoDB：更新同一文档的嵌套元素中的字段

1 个答案: