从客户端

Question

当我在服务器端代码中抛出HttpResponseException时，我似乎无法找到检索错误消息的方法。

这是我用来捕获未处理的服务器端异常的全局异常过滤器：

public class ExceptionHandlingAttribute : ExceptionFilterAttribute
{
    private static readonly Logger Nlog = LogManager.GetCurrentClassLogger();

    public override void OnException(HttpActionExecutedContext context)
    {
        string message = context.Exception.Message;

        throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.InternalServerError)
        {
            Content = new StringContent(message),
            ReasonPhrase = "Exception"
        });
    }
}

这是我的客户端代码（angular2）：

    getAll(): Observable<T[]> {
    let url_ = `${this.localUrl}`;
    return this.http.request(url_
    ).map((response) => {
        return this.processArrayResponse(response);
    }).catch((response: any, caught: any) => {
        console.log(response)
        return this.handleArrayResponseError(response);
    });
}

    protected handleAnyResponseError(response: any): Observable<any> {
    if (response instanceof Response) {
        try {
            return Observable.of(this.processAnyResponse(response));
        } catch (e) {
            console.log(e)
            return <Observable<any>><any>Observable.throw(e);
        }
    } else
        return <Observable<any>><any>Observable.throw(response);
}

我得到的回应是：

Response {_body: ArrayBuffer, status: 500, ok: false, statusText: "Exception", headers: Headers…}
headers:Headers
ok:false
status:500
statusText:"Exception"
type:2
url:"http://localhost:83/api/PreHeatSchedule/getExportFile"
_body:ArrayBuffer
__proto__: Body

我不知道如何从客户端的异常中获取Content部分。