Question

我有以下内容：

CREATE TABLE food_delivery
(
    foodtype varchar(50) NOT NULL,
    foodname varchar(50) NOT NULL,
    numitems int NOT NULL
)
go

INSERT INTO food_delivery
VALUES 
('vegetable', 'carrot', 30), 
('vegetable', 'carrot', 50), 
('vegetable', 'potato', 40),
('vegetable', 'potato', 60),
('fruit', 'apple', 50),
('fruit', 'apple', 70),
('fruit', 'banana', 60),
('fruit', 'banana', 80)
GO

现在，当我运行此查询时：

SELECT foodtype, foodname, SUM(numitems)
FROM food_delivery
GROUP BY foodtype, foodname WITH ROLLUP

我明白了：

foodtype     foodname     
------------ ------------ -----------
fruit        apple        120
fruit        banana       140
fruit        NULL         260
vegetable    carrot       80
vegetable    potato       100
vegetable    NULL         180
NULL         NULL         440

我很满意这个订单，但我也希望为每种食物类型中的项目添加排名，以便我有这样的事情：

foodtype     foodname                 
------------ ------------ ----------- --------------------
fruit        apple        120         1
fruit        banana       140         2
fruit        NULL         260         3
vegetable    carrot       80          1
vegetable    potato       100         2
vegetable    NULL         180         3
NULL         NULL         440         1

我的想法是，我想识别排名为1的行并对它们进行不同的处理。

所以这是我使用的查询：

SELECT foodtype, foodname, SUM(numitems), 
         ROW_NUMBER() OVER (PARTITION BY foodtype ORDER BY foodname, SUM(numitems))
FROM food_delivery
GROUP BY foodtype, foodname WITH ROLLUP

不幸的是，添加ROW_NUMBER（）完全抛出了我的结果集的排序，我得到了这个：

foodtype     foodname                 
------------ ------------ ----------- --------------------
NULL         NULL         440         1
fruit        NULL         260         1
fruit        apple        120         2
fruit        banana       140         3
vegetable    NULL         180         1
vegetable    carrot       80          2
vegetable    potato       100         3

即。摘要位于每个组的顶部而不是底部。

有人能告诉我如何在每个小组的底部获取我的摘要，同时仍然有我的排名？

感谢。

编辑：所以Jon Seigel的答案给了我我想要的东西，但我仍然不明白为什么其他解决方案不起作用。

拿这个：

SELECT  CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END,
        foodtype,  
        CASE WHEN foodname IS NULL THEN 0 ELSE 1 END,
        foodname,  
        SUM(numitems),   
        ROW_NUMBER() OVER (PARTITION BY foodtype 

ORDER BY    CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END, 
            foodtype, 
            CASE WHEN foodname IS NULL THEN 0 ELSE 1 END, 
            foodname DESC)  RankVal 

FROM    food_delivery  
GROUP BY    foodtype,  
            foodname WITH ROLLUP  

ORDER BY    CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END, 
            foodtype, 
            CASE WHEN foodname IS NULL THEN 0 ELSE 1 END, 
            foodname DESC

这与Jon的解决方案几乎完全相同，只是我将订单设为降序，并将 1 和 0 转置于< strong>那么0 ELSE 1 。在我看来，这应该给我相同的结果（即NULLS将为0，因为它们被排序为DESC，它们应该出现在集合的底部）。然而，返回的结果集是：

            foodtype                 foodname                 RankVal
----------- ------------ ----------- ------------ ----------- --------------------
0           NULL         0           NULL         440         1
1           fruit        0           NULL         260         1
1           fruit        1           banana       140         2
1           fruit        1           apple        120         3
1           vegetable    0           NULL         180         1
1           vegetable    1           potato       100         2
1           vegetable    1           carrot       80          3

如您所见，CASE语句的结果未按DESCending顺序排序。

Answer 1

尝试明确指定ORDER BY。

像

这样的东西

SELECT  foodtype, 
        foodname, 
        SUM(numitems),  
        ROW_NUMBER() OVER (PARTITION BY foodtype ORDER BY foodname, SUM(numitems)) RankVal
FROM    @food_delivery 
GROUP BY    foodtype, 
            foodname WITH ROLLUP 

ORDER BY    CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END,
            foodtype,
            CASE WHEN foodname IS NULL THEN 1 ELSE 0 END,
            foodname,
            RankVal

Answer 2

SELECT
    foodtype,
    foodname,
    NumItems,
    ROW_NUMBER() OVER
    (
        PARTITION BY foodtype
        ORDER BY
            (CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END),
            foodtype,
            (CASE WHEN foodname IS NULL THEN 1 ELSE 0 END),
            foodname
    ) AS Rank
    FROM
    (
        SELECT
            foodtype,
            foodname,
            SUM(numitems) AS NumItems
            FROM food_delivery
            GROUP BY foodtype, foodname WITH ROLLUP
    ) a
    ORDER BY
        (CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END),
        foodtype,
        (CASE WHEN foodname IS NULL THEN 1 ELSE 0 END),
        foodname

添加row_number会影响汇总中的行顺序

2 个答案: