Question

我真的很难在2d阵列中输入用户输入的单词。我的程序需要做的是创建一个单词搜索拼图，提示用户他或她想要找到多少单词，以及给定的单词将是什么。我遇到的问题是我似乎无法将用户的输入放在2d数组中。以下是我目前的代码：

 public static void generate(){
      int rows = 5;
      int columns = 5;
      char[][] table = new char [rows][columns];
      int numberwanted;

      System.out.println("Type in the number of words you want to generate: ");
      numberwanted = userinput.nextInt();
      System.out.println("Type in the words you want to generate: ");
      for (int i = 0; i < numberwanted; i++){
         String words = userinput.next();
         char te = words.charAt(i);
         for(int r = 0; r < rows; r++){
            for(int c = 0; c < columns; c++){
               table[r][c] = te;
               System.out.print(table[r][c] + " ");
            }
            System.out.println();
         }

      }// forloop

输出：

Type in the number of words you want to generate: 
2
Type in the words you want to generate: 
test
t t t t t 
t t t t t 
t t t t t 
t t t t t 
t t t t t

目标输出：

Type in the number of words you want to generate: 
2
Type in the words you want to generate: 
test
hi
t e s t x          x x t x x
x x x x x    or    x x e x x   and so on... with x's being empty
x h x x x          x x s x x 
x i x x x          x x t x x
x x x x x          x x h i x

Answer 1

您需要更新字符串中的所有字符。在你的情况下，你只有字符串的第一个字符。

    public static void generate(){
          int rows = 5;
          int columns = 5;
          char[][] table = new char [rows][columns];
          int numberwanted;
          Scanner sc = new Scanner(System.in);
          System.out.println("Type in the number of words you want to generate: ");
          numberwanted = sc.nextInt();
          System.out.println("Type in the words you want to generate: ");
          int j=0;
          for (int i = 0; i < numberwanted; i++){
             String words = sc.next();
             char te = ' ';
             for(int r = 0; r < rows; r++){
                for(int c = 0; c < columns; c++){
                    if(j<words.length()) te = words.charAt(j++);
                    else te = '*';
                   table[r][c] = te;
                   System.out.print(table[r][c] + " ");

                }
                System.out.println();
             }

          }
}

<强>更新。如果你只想要对角线元素。这是

public static void generate(){
          int rows = 5;
          int columns = 5;
          char[][] table = new char [rows][columns];
          int numberwanted;
          Scanner sc = new Scanner(System.in);
          System.out.println("Type in the number of words you want to generate: ");
          numberwanted = sc.nextInt();
          System.out.println("Type in the words you want to generate: ");
          int j=0;
          for (int i = 0; i < numberwanted; i++){
             String words = sc.next();
             char te = ' ';
             for(int r = 0; r < rows; r++){
                for(int c = 0; c < columns; c++){
                    if(j<words.length() && r==c) te = words.charAt(j++);
                    else te = '*';
                   table[r][c] = te;
                   System.out.print(table[r][c] + " ");

                }
                System.out.println();
             }

          }
}

希望这有帮助

Answer 2

我调整了整个程序，使其更加强大。它现在如何运作：

处理table。
如果用户想提供一个单词，请询问单词。
将单词（可能是截断的）添加到当前row。
右侧填充x行。

最后，渲染整个table。

private static int ROWS = 5;
private static int COLUMNS = 5;

public static void main(String[] args) {
    char[][] table = new char[ROWS][COLUMNS];
    int numberwanted;
    try (Scanner in = new Scanner(System.in)) {
        System.out.println("Type in the number of words you want to generate: ");
        numberwanted = Math.min(in.nextInt(), ROWS);

        for (int row = 0; row < ROWS; row++) {
            String word = null;
            if (row < numberwanted) {
                System.out.println(String.format("Type in the %d. word: ", row));
                word = in.next();
            }
            for (int col = 0; col < COLUMNS; col++) {
                table[row][col] = word != null && word.length() > col ? word.charAt(col) : 'x';
            }
        }
    }
    renderGrid(table);
}

private static void renderGrid(char[][] grid) {
    for (int row = 0; row < ROWS; row++) {
        for (int col = 0; col < COLUMNS; col++) {
            System.out.print(grid[row][col] + " ");
        }
        System.out.println();
    }
}

把用户输入的单词放在java中的2d数组中

2 个答案: