c＃json重新排列相同的值

Question

你如何在c＃

中制作下面的json

[
 {"file": "fileName1", "key":0, title:"u1"},
 {"file": "fileName1", "key":2, title:"u1"},
 {"file": "fileName2", "key":5, title:"u1"},
 {"file": "fileName2", "key":10, title:"u1"}
]

进入这个。

{ 
 "fileName1" : [{"key":0, title:"u1"},{"key":2, title:"u1"}],
 "fileName2" : [{"key":0, title:"u1"},{"key":2, title:"u1"}]
}

谢谢

Answer 1

我已经为你做了一个小提琴 https://dotnetfiddle.net/Wsnl9V

using System;
using System.Collections.Generic;
using System.Linq;
using Newtonsoft.Json;


public class Program
{
    public static void Main()
    {
        string input = @"[ 
             {'file': 'fileName1', 'key':0, title:'u1'},
             {'file': 'fileName1', 'key':2, title:'u1'},
             {'file': 'fileName2', 'key':5, title:'u1'},
             {'file': 'fileName2', 'key':10, title:'u1'}
        ]";

        var existingList = JsonConvert.DeserializeObject<List<CurrentType>>(input);

        var dictionary = new Dictionary<string,List<RequiredTypeFile>>();


        var distinctFileNames =  existingList.Select(x=> x.File).Distinct().ToList();

        distinctFileNames.ForEach(x=>
                                  {
                                      var fileValue = existingList.Where(m=>m.File==x)
                                        .Select(m => new RequiredTypeFile
                                                {
                                                    Key = m.Key,
                                                    Title = m.Title
                                                }).ToList();
                                      dictionary.Add(x,fileValue);
                                  });

        var reqdJson = JsonConvert.SerializeObject(dictionary);


        Console.WriteLine(reqdJson);
    }
}

public class CurrentType
{
    public string File
    {
        get;
        set;
    }

    public int Key
    {
        get;
        set;
    }

    public string Title
    {
        get;
        set;
    }
}

public class RequiredTypeFile
{
    public int Key
    {
        get;
        set;
    }

    public string Title
    {
        get;
        set;
    }

}