将用户输入数组传递给方法并返回一个整数?

时间:2017-04-26 01:44:57

标签: java

如何将用户输入传递给方法然后让该方法返回整数或双精度?我一直得到一个错误,我必须返回一个整数,但我不明白如何。

import java.util.Scanner; 

public class Q7_8 {

    public static void main(String [] args){
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter 10 integers:");
        int[] a = new int[10];

        for(int i =0; i < a.length; i++){
            a[i] = sc.nextInt();
        }
        average(a);
    }
    public static int average(int [] array){
        int sum =0;
        for(int i = 0; i < array.length; i++){
            sum += array[i];
            int finalAvr = array[i] /10;
        }
    }
    public static double average(double [] array){
        int sum =0;
        for(int i = 0; i < array.length; i++){
            sum += array[i];
            double finalAvr = array[i] /10;
        }
    }
}

2 个答案:

答案 0 :(得分:0)

警告我不仅仅是一个C ++人,但它仍然应该是类似的:

public static int average(int [] array){
    int sum =0;
    for(int i = 0; i < array.length; i++){
        sum += array[i];
        int finalAvr = array[i] /10;
    }
    return sum / 10; // you need to return the average you calculated
}

双倍的平均值相同。你错过了这一行:

return sum / 10.0;

答案 1 :(得分:-1)

       public static void main(String [] args){
            Scanner sc = new Scanner(System.in);
            System.out.println("Enter 10 integers:");
            int[] a = new int[10];

            for(int i =0; i < a.length; i++){
                a[i] = sc.nextInt();
            }
            double avg = average(a); //if average return something, then you must assign the value return somwhere.
            System.out.println(avg); // print the valued return - avg
        }
        public static int average(int [] array){
            int sum =0;
            for(int i = 0; i < array.length; i++){
                sum += array[i];
            }
            return (int)(sum/array.length); //must return if you specify return type
        }
        public static double average(double [] array){
            double sum =0;
            for(int i = 0; i < array.length; i++){
                sum += array[i];
            }
            return sum/array.length; //must return if you specify return type
        }

参考文献: https://docs.oracle.com/javase/tutorial/java/javaOO/returnvalue.html