Question

我有一个网页，需要将数据发送回MySQL数据库，但前两个表格框数据不会发送到数据库。

我的php mysql知识非常有限，无法自己解决问题。

//create the connection 
$conn = mysqli_connect($servername, $username, $password, $dbname);

if(!$conn)
{

//Error handler
die("MySQL Connection Error: ".mysqli_error());
}

//Extracting information from the user to add to the outputs table in the Database
if (isset($_POST['confirmbut'])) {
    $sensorname = mysqli_real_escape_string($conn,$_POST['sensorname']);
    $sensorip = mysqli_real_escape_string($conn,$_POST['sensorip']);
    $state = mysqli_real_escape_string($conn,$_POST['state']);

//Selecting Database and inserting user inputted data to the database
    mysqli_query($conn,"SELECT * FROM outputs");
    mysqli_query($conn,"INSERT INTO outputs(Sensor_ID, Sensor_IP, State, Pending_Update) VALUES ('$sensorname', '$sensorip','$state','1')");

    header("location: insertname.php");
}


?>

<!DOCTYPE html>
    <html>
        <head>
        <meta charset="utf-8">
        <title> Switch </title>
    </head>
<body>

<h2 class="title">Please fill in your switches Details</h2>

    <!-- Posts data inserted here -->
    <form method="post" action="insertname.php">

        <!-- Form to enter Device Name, Output IP, State --> 
        <tr>    
            <td>  Relay Name: </td>
            <td><input type="text" name="output name" class="textInput" required="required"></td>
        </tr> 

        <tr>
            <td>  Relay IP:</td>
            <td><input type="text" name="outputIP" class="textInput" required="required"></td>
        </tr>

        <tr>
            <td>  Relay State: On = 1  Off = 0</td>
            <td><input type="text" name="state" class="textInput" required="required"></td>
        </tr>
            <td><input type="submit" name="confirmbut" value="Enter" class="enterbutton" > </td>
        </tr>

       </form>  
    </body>
 </html>

Answer 1

我不知道您是否更改了数据库中表行的名称，但假设它们与代码中的相同，我更正了您的代码，以便您尝试插入的字段是从表格中的正确输入中提取。

if(!$conn)
{

//Error handler
die("MySQL Connection Error: ".mysqli_error());
}

//Extracting information from the user to add to the outputs table in the Database
if (isset($_POST['confirmbut'])) {
    $outputname = mysqli_real_escape_string($conn,$_POST['outputname']);
    $outputip = mysqli_real_escape_string($conn,$_POST['outputip']);
    $state = mysqli_real_escape_string($conn,$_POST['state']);

//Selecting Database and inserting user inputted data to the database
    mysqli_query($conn,"SELECT * FROM outputs");
    mysqli_query($conn,"INSERT INTO outputs(Sensor_ID, Sensor_IP, State, Pending_Update) VALUES ('$outputname', '$outputip','$state','1')");

    header("location: insertname.php");
}


?>

<!DOCTYPE html>
    <html>
        <head>
        <meta charset="utf-8">
        <title> Switch </title>
    </head>
<body>

<h2 class="title">Please fill in your switches Details</h2>

    <!-- Posts data inserted here -->
    <form method="post" action="insertname.php">

        <!-- Form to enter Device Name, Output IP, State --> 
        <tr>    
            <td>  Relay Name: </td>
            <td><input type="text" name="outputname" class="textInput" required="required"></td>
        </tr> 

        <tr>
            <td>  Relay IP:</td>
            <td><input type="text" name="outputip" class="textInput" required="required"></td>
        </tr>

        <tr>
            <td>  Relay State: On = 1  Off = 0</td>
            <td><input type="text" name="state" class="textInput" required="required"></td>
        </tr>
            <td><input type="submit" name="confirmbut" value="Enter" class="enterbutton" > </td>
        </tr>

       </form>  
    </body>
 </html>

网页表单没有向mysql数据库发送输入

1 个答案: