Question

目标：多个日期/交易的SUM / AVG客户数据。详细问题：如何正确分组客户端（＆＃39; PlayerID＆＃39;）然后SUM整个int（MinsPlayed），然后是AVG（AvgBet）？当前问题：我的结果是在90天内逐日提供个别交易，而不是在90天内提供SUM / AVG。

Current Script/Results: FirstName-Riley is showing each individual daily transaction instead of 1 total SUM/AVG over set time period

Answer 1

首先，您不需要使用DISTINCT，因为您将使用GROUP BY聚合结果，因此您可以将其取出。

您为每个事务返回一行的原因是您的GROUP BY子句包含您尝试聚合的列（例如TimePlayed）。通常，您只希望GROUP BY not 聚合的列，因此从使用SUM或AVG（TimePlayed，PlayerSkill等）聚合的GROUP BY子句中删除所有列。

Answer 2

这是您当前的SQL：

SELECT DISTINCT CDS_StatDetail.PlayerID, 
    StatType,
    FirstName,
    LastName,
    Email,
    SUM(TimePlayed)/60 AS MinsPlayed,
    SUM(CashIn) AS AvgBet,
    SUM(PlayerSkill) AS AvgSkillRating,
    SUM(PlayerSpeed) AS Speed,
    CustomFlag1
FROM CDS_Player INNER JOIN CDS_StatDetail
ON CDS_Player.Player_ID = CDS_StatDetail.PlayerID
WHERE StatType='PIT' AND CDS_StatDetail.GamingDate >= '1/02/17' and CDS_StatDetail.GamingDate <= '4/02/2017' AND CustomFlag1='N'
GROUP BY CDS_StatDetail.PlayerID, StatType, FirstName, LastName, Email, TimePlayed, CashIn, PlayerSkill, PlayerSpeed, CustomFlag1
ORDER BY CDS_StatDetail.PlayerID

你想要这样的东西：

SELECT CDS_StatDetail.PlayerID, 
    SUM(TimePlayed)/60 AS MinsPlayed,
    AVG(CashIn) AS AvgBet,
    AVG(PlayerSkill) AS AvgSkillRating,
    SUM(PlayerSpeed) AS Speed,
FROM CDS_Player INNER JOIN CDS_StatDetail
ON CDS_Player.Player_ID = CDS_StatDetail.PlayerID
WHERE StatType='PIT' AND CDS_StatDetail.GamingDate BETWEEN '2017-01-02' AND '2017-04-02' AND CustomFlag1='N'
GROUP BY CDS_StatDetail.PlayerID

下次请复制并粘贴文字，而不仅仅是链接到屏幕截图。

SQL-如何随着时间的推移对客户端数据求和？

2 个答案: