Question

大家好我有一个问题。我有一个动态填充的数组。在数组中有2种主要类型的项目。文件名等于27个字符的项目，其余的或多或少。我能分开两种类型。第二个列表被添加到名为$ usedArray的新数组中。然后迭代这些项目，文件名从字符0,6继承，用于比较页面上的最终用户输入。如果在该数组中找到该项，它将触发一个函数，向它们发送文本和完整文件名的电子邮件。我的问题是，如果在x次迭代之前找不到该项，它将触发未找到的函数x次数，如果它根本找不到它会做同样的事情。如果我有99件不匹配的物品会发射99次。停止射击我离开了未找到只是在屏幕上找不到的打印。我想在循环外部调用notfound函数，但是如果找到了一个项目则不希望它被触发这是我到目前为止的代码

do{
    if (substr($val,0,6) == $studentID)
    {

        $codeFound = substr($val,22,19);
        print_r($studentID . ' is found <br /> Their code is ' . $codeFound);
        //sendText($phoneNum,$codeFound,$messageMonth);
        //sendEmail($emailInfo,$messageMonth,$codeFound);
        break 1;

    }
    else
    {
        print_r($studentID . " was not found <br />");
    }

} while(list(, $val) = each($usedArray));

这是我的输出

166003 was not found
166003 was not found
166003 was not found
166003 is found
Their code is xxxxxxxxxx

Answer 1

我认为你应该添加一个标志来跟踪你是否找到了什么：

$item_found = false;
do{
    if (substr($val,0,6) == $studentID)
    {

        $codeFound = substr($val,22,19);
        print_r($studentID . ' is found <br /> Their code is ' . $codeFound);
        //sendText($phoneNum,$codeFound,$messageMonth);
        //sendEmail($emailInfo,$messageMonth,$codeFound);

        // item found!
        $item_found = true;

        break 1;
    }
} while(list(, $val) = each($usedArray));

// now check - if `$item_found` is false 
// then you can send your NotFoundEmail
if (!$item_found) {
    sendNotFoundEmail();
}

当找到项目结束循环但未找到调用函数时，遍历数组

1 个答案: