Question

我正在尝试编写图像旋转，但我现在遇到了一些问题。这是我的代码：

mutualFund

不幸的是这段代码不起作用。我得到这样的错误：

Mat rotateMagnify (Mat& img, int degree){
double angle = degree  * CV_PI / 180.;
double a = sin(angle), b = cos(angle);

int width = img.cols, height = img.rows;

int width_rotate = int(height * fabs(b) - width * fabs(a) + width);
int height_rotate = int(width * fabs(a) + height * fabs(b) + height);

Mat img_rotate;
img_rotate.create((width_rotate, height_rotate), img.depth(), img.channels());


int tempLength = sqrt((double)width * width + (double)height *height) + 10;
int tempX = (tempLength + 1) / 2 - width / 2;
int tempY = (tempLength + 1) / 2 - height / 2;


Mat temp;
temp.create((tempLength, tempLength), img.depth(), img.channels());
//cvZero(&img_rotate);

Mat roiImage = temp(Rect(Point(tempX, tempY), Point(width, height)));

//roiImage.ResetImageROI(roiImage);

img.copyTo(roiImage);

float m[6];
int w = roiImage.cols;
int h = roiImage.rows;
m[0] = b;
m[1] = a;
m[3] = -m[1];
m[4] = m[0];

m[2] = w * 0.5f;
m[5] = h * 0.5f;
CvMat M = cvMat(2, 3, CV_32F, m);

cvGetQuadrangleSubPix(&roiImage, &img_rotate, &M);
roiImage.release();

return img_rotate;}

如何修复此错误。谢谢大家的帮助！

Answer 1

当您尝试复制（裁剪）图像的一部分时，通常会抛出此错误，但您指定的x，y值要么是-ve，要么是大于实际图像的大小。在尝试

之前，添加断点并检查

int tempX = (tempLength + 1) / 2 - width / 2;
int tempY = (tempLength + 1) / 2 - height / 2;

的值以尝试处理上述条件

Mat roiImage = temp（Rect（Point（tempX，tempY），Point（width，height）））;

// roiImage.ResetImageROI（roiImage）;

img.copyTo（roiImage）;

关于rect ROI的OpenCv断言失败了

1 个答案: