使用Stub抛出ExpectedException TimeoutException不起作用c#

时间:2017-04-25 15:27:52

标签: c# .net unit-testing stub timeoutexception

我有这个单元测试,而且我一直试图对它进行例外处理,但是我无法做到,请你能帮助我吗?

    [TestMethod]
    [ExpectedException(typeof(TimeoutException))]
    public async Task HandleAsyncDeleteModel_WhenRepositoryFails_ThrowsException()
    {
        //Arrange
        var token = new CancellationToken();
        var deleteModel = new DeleteProcessCommand(_img, _tnt, _pro, _url);
        var writeRepository = new StubIWriteRepository<Dto>()
        {
            DeleteIfExistsAsyncGuidGuidGuidCancellationToken = (img, tnt, pro, tkn) =>
            { 
                throw new TimeoutException();
            }
        };

        var Logger = new StubILogger();
        var commandHandler = new CommandHandler(Logger, writeRepository, null, null, null, null, null, null);

        //Act
        await commandHandler.HandleAsync(deleteModel, token);
    }

1 个答案:

答案 0 :(得分:0)

单元测试不等待异步方法。没有人要求异步方法的结果。你需要做一个.Wait来迫使它等待结果。

[TestMethod]
[ExpectedException(typeof(TimeoutException))]
public async Task HandleAsyncDeleteModel_WhenRepositoryFails_ThrowsException()
{
    //Arrange
    var token = new CancellationToken();
    var deleteModel = new DeleteProcessCommand(_img, _tnt, _pro, _url);
    var writeRepository = new StubIWriteRepository<Dto>()
    {
        DeleteIfExistsAsyncGuidGuidGuidCancellationToken = (img, tnt, pro, tkn) =>
        { 
            throw new TimeoutException();
        }
    };

    var Logger = new StubILogger();
    var commandHandler = new CommandHandler(Logger, writeRepository, null, null, null, null, null, null);

    //Act
    commandHandler.HandleAsync(deleteModel, token).Wait();
}