Question

当我按下CodeIgniter中表单上的提交按钮时，如果我在XController/loadX 我的行动是YController/loadY，网址变为Xcontroller/loadX/Ycontriller/loadY，我希望它只是YController/loadY。

  <form name="SpecAccept"method="post"action="SpecialistController/loadDoctor">
    <div class="form-group col-sm-12" id="myDiv" align="right">
        <span><label>الولاية</label></span>
        <select style="font-size:12px"  class="form-control" id="state_name" onchange="change(this)">
            <option>--- اختر الولاية ---</option>
            <?php
                foreach($states as $Object){
                echo '<option value="'.$Object->StateID.'">'.$Object->StateName.'</option>';
                }
            ?>

        </select>   
    </div>
    <div class="form-group col-sm-6" id="myDiv" align="right">
        <span><label>المهنة</label></span>
        <select style="font-size:12px" class="form-control" id="career_name" >
            <option>--- اختر المهنة ---</option>
            <?php
                foreach($careers as $Object){
                echo '<option value="'.$Object->CareerID.'">'.$Object->CareerName.'</option>';
                }
            ?>

        </select>   
    </div>
    <div class="form-group col-sm-6" id="myDiv" align="right">
        <span><label>المستشفى</label></span>
        <select style="font-size:12px"  class="form-control" id="hospitals" name="Hospitals" >
            <option value="0" isSelected>اختر الولاية اولاً</option>
        </select>
    </div>                                          
   <div class="form-group col-sm-12">
    <button type="sumbit">عرض</button>
    </div>
</form>

问题是什么以及如何解决？

Answer 1

尝试使用javascript

<button type="button" onclick="Function_name();" >عرض</button>

然后在javascript中你可以做到

<script>
function Function_name(){
alert ('I AM HERE');
document.SpecAccept.submit();
}
   </script>

警告是查看该按钮是否有效并输入该功能。

如果不起作用，请尝试更改此类型的表单

<?php
    $attributes = array(
                    'id' => 'SpecAccept',
                    'name' => 'SpecAccept',
                    'autocomplete' => 'off',
                    'enctype' => 'multipart/form-data',
                );
               echo form_open_multipart('SpecialistController/loadDoctor'); // this is the open <form>
?>

然后关闭它会替换<{p>的</form>标记

<?php echo form_close();?>

Answer 2

首先，您需要在config.php文件中定义基本URL，如此

$config['base_url'] = 'http://localhost/projectfoldername/';

现在使用表单操作网址

<form name="SpecAccept"method="post"action="<?php echo base_url('SpecialistController/loadDoctor'); ?> ">

URL不像我想要的那样

2 个答案: