Python从文件中删除一行行

时间:2017-04-25 14:34:47

标签: python file-handling

我正在努力弄清楚如何从文件中删除一行代码。以下是代码

#!/usr/bin/python
import argparse
import re
import string

##getting user inputs
p = argparse.ArgumentParser()
p.add_argument("input", help="input the data in format ip:port:name", nargs='*')  
args = p.parse_args()
kkk_list = args.input


def printInFormat(ip, port, name):
    formattedText = '''HOST Address:{ip}:PORT:{port} 
                        mode tcp 
                        bind {ip}:{port} name {name}'''.format(ip=ip, 
                                                                port=port, 
                                                                name=name)
    textWithoutExtraWhitespaces =  '\n'.join([line.strip() for line in formattedText.splitlines()])
    # you can break above thing
    # text = ""
    # for line in formattedText.splitlines():
    #       text += line.strip()
    #       text += "\n" 

    return(formattedText)

#####here im writing writing the user inoput to a file and it works great.
#with open("file.txt", "a") as myfile:
#    for kkk in kkk_list:
#         ip, port, name = re.split(":|,", kkk)
#         myfile.write(printInFormat(ip, port, name))

###### here is where im struggling. 
for kkk in kkk_list:
    ip, port, name = re.split(":|,", kkk)
    tobedel = printInFormat(ip, port, name)  
    f = open("file.txt", "r+")
    d = f.readlines()
    f.seek(0)
    if kkk != "tobedel":
        f.write(YY)
f.truncate()
f.close()

正如您所看到的,我正在使用用户输入附加file.txt。即(格式:ip:port:name)。当脚本被执行时,文件将包含以下条目./script.py 192.168.0.10:80:string 192.168.0.10:80:string

Host Address:192.168.0.10:PORT:80
mode tcp
bind 192.168.0.10:80 abc    
Host Address:10.1.1.10:PORT:443
mode tcp
bind 10.1.1.10:443 xyz

现在我想以相同的方式从用户输入中删除file.txt中的行。运行上面的代码没有任何反应。如果你能帮我理解,我是初学者并且非常乐于助人。此问题与python multiple user args

有关

2 个答案:

答案 0 :(得分:1)

让我指出你遗漏的小事。

for kkk in kkk_list:
    ip, port, name = re.split(":|,", kkk)
    tobedel = printInFormat(ip, port, name)  
    f = open("file.txt", "r+")
    d = f.readlines()
    f.seek(0)
    if kkk != "tobedel":
        f.write(YY)
f.truncate()
f.close()
  1. 您在循环内打开文件并关闭外部。文件对象超出范围。使用with自动处理上下文。

  2. 在循环中打开文件是个坏主意,因为它会创建如此多的文件描述符,从而消耗大量资源。

  3. 你写作时从未提及YY是什么。

  4. 您可以在此处删除行,因为您尝试一次删除多行,因此d = f.readlines()应为d = f.read()

  5. 以下是更新的代码。

    #!/usr/bin/python
    import argparse
    import re
    import string
    
    p = argparse.ArgumentParser()
    p.add_argument("input", help="input the data in format ip:port:name", nargs='*')  
    args = p.parse_args()
    kkk_list = args.input # ['192.168.1.10:80:name1', '172.25.16.2:100:name3']
    
    
    def getStringInFormat(ip, port, name):
        formattedText = "HOST Address:{ip}:PORT:{port}\n"\
                        "mode tcp\n"\
                        "bind {ip}:{port} name {name}\n\n".format(ip=ip, 
                                                                    port=port, 
                                                                    name=name)
    
        return formattedText
    
    # Writing the content in the file
    # with open("file.txt", "a") as myfile:
    #    for kkk in kkk_list:
    #         ip, port, name = re.split(":|,", kkk)
    #         myfile.write(getStringInFormat(ip, port, name))
    
    
    
    with open("file.txt", "r+") as f:
        fileContent = f.read()
    
        # below two lines delete old content of file
        f.seek(0)
        f.truncate()
    
        # get the string you want to delete
        # and update the content
        for kkk in kkk_list:
            ip, port, name = re.split(":|,", kkk)
    
            # get the string which needs to be deleted from the file
            stringNeedsToBeDeleted = getStringInFormat(ip, port, name)
    
            # remove this from the file content    
            fileContent = fileContent.replace(stringNeedsToBeDeleted, "")
    
        # delete the old content and write back with updated one
        # f.truncate(0)
        f.write(fileContent)
    
    # Before running the script file.txt contains 
    
    # HOST Address:192.168.1.10:PORT:80
    # mode tcp
    # bind 192.168.1.10:80 name name1
    #
    # HOST Address:172.25.16.2:PORT:100
    # mode tcp
    # bind 172.25.16.2:100 name name3
    
    # After running file.txt will be empty
    # as we have deleted both the entries.
    

答案 1 :(得分:0)

有多种方法可以做到。我试图创建一个新文件,留下所有块。您可以删除旧文件并将新文件重命名为旧文件。 以下是相同的工作代码。

 #!/usr/bin/python
 import argparse
 import re
 import string

##getting user inputs
p = argparse.ArgumentParser()
p.add_argument("input", help="input the data in format ip:port:name", nargs='*')  
args = p.parse_args()
kkk_list = args.input # ['192.168.1.10:80:name1', '172.25.16.2:100:name3']



# returns the next block from the available file. Every block contains 3 lines as per definition.
def getNextBlock(lines, blockIndex):
    if len(lines) >= ((blockIndex+1)*3):
        line = lines[blockIndex*3]
        line += lines[blockIndex*3+1]
        line += lines[blockIndex*3+2]
    else:
        line = ''

    return line

# file  - holds reference to existing file of all blocks. For efficiency keep the entire content in memory (lines variable)
file = open("file.txt", "r")
lines = file.readlines()
linesCount = len(lines)

# newFile holds reference to newly created file and it will have the resultant blocks after filtering
newFile = open("file_temp.txt","w")


# loop through all inputs and create a dictionary of all blocks to delete. This is done to have efficiency while removing the blocks with O(n) time

delDict = {}
for kkk in kkk_list:
    ip, port, name = re.split(":|,", kkk)
    tobedel = printInFormat(ip, port, name)
    delDict[tobedel] = 1

for i in range(linesCount / 3):
    block = getNextBlock(lines, i)
    if block in delDict:
        print 'Deleting ... '+block
    else:
        #write into new file
        newFile.write(block)

file.close()
newFile.close()

#You can drop the old file and rename the new file as old file

希望它有所帮助!