Question

所以，我有一个返回下表的查询：

charvar | numeric | numeric           |   numeric  | text
 cargo  |   qtd   | valor_ust_servico |  total_ust | valor_servco

 name1  |   30    |   0.50  |  236.50 | US$ 20,132.02
 name2  |   96    |   0.50  |  236.50 | US$ 43,169.32
 name3  |   120   |   0.50  |  236.50 | US$ 12,791.11
 name4  |  7708   |   0.50  |  236.50 | US$ 142,041.64
 name5  |   469   |   0.50  |  236.50 | US$ 5,984.18

我需要在决赛桌上添加name1和name3。

我的代码如下

    with consulta as
(  
  SELECT
          cc.nomecategoriaservico,
          max(s.nomeservico) as nomeservico,
          min(vsc.valorServico) as valor_UST_Serviço,
          sum(vsc.valorservico) as total_UST,
          sum(vsc.valorServico*c.cotacaomoeda) as Valor_Serviço,
          count(s.nomeservico) as qtd,
          EXTRACT(MONTH FROM SS.DATAHORAFIM) AS MESSERVICO
        FROM solicitacaoservico ss
        INNER JOIN SERVICOCONTRATO SC ON SC.IDSERVICOCONTRATO = SS.IDSERVICOCONTRATO
        INNER JOIN VALORSERVICOCONTRATO VSC ON VSC.IDSERVICOCONTRATO = SC.IDSERVICOCONTRATO
        INNER JOIN CONTRATOS C ON C.IDCONTRATO = SC.IDCONTRATO
        INNER JOIN SERVICO S ON S.IDSERVICO = SC.IDSERVICO
        left JOIN CATEGORIASERVICO CC ON S.IDCATEGORIASERVICO = CC.IDCATEGORIASERVICO
        WHERE ss.datahorafim BETWEEN '2017-03-01 00:00:00' AND '2017-03-31 23:59:59.999'
        AND UPPER(SS.SITUACAO) = UPPER('FECHADA')
        GROUP BY CC.NOMECATEGORIASERVICO, EXTRACT(MONTH FROM SS.DATAHORAFIM)
), consolidado as
 (
     select
     0 as linha,
     nomecategoriaservico AS CARGO,
     qtd,
     valor_UST_Serviço,
     total_UST AS total_UST,
     'R$' || to_char(Valor_Serviço,'9G999G999D99') as Valor_Serviço
  FROM consulta
  UNION ALL
  SELECT
    1 as linha,
    'Total UST' as CARGO,
    sum(qtd) as qtde,
    round(sum(qtd*valor_UST_Serviço)/sum(qtd),2) valor_UST_Serviço,
    sum(total_UST) as total,
    'R$' || to_char(sum(Valor_Serviço),'9G999G999D99') as Valor_Serviço
  FROM consulta
), fim AS (
select
  CARGO,
  qtd,
  valor_UST_Serviço,
  total_UST,
  REPLACE(REPLACE(REPLACE(Valor_Serviço,'  ',' '),'  ',' '),'  ',' ') AS Valor_Serviço
from consolidado
order by linha,CARGO

到目前为止，我所尝试过的所有内容都很接近，但不是很正确。由于格式不同，我也会得到很多错误。

EDIT1。但格式化

Answer 1

CTE别名咨询：

  SELECT
          case when cc.nomecategoriaservico = 'name1' or name_col = 'name3' then 'name1or3' else cc.nomecategoriaservico end nomecategoriaservico,
          max(s.nomeservico) as nomeservico,
          min(vsc.valorServico) as valor_UST_Serviço,
          sum(vsc.valorservico) as total_UST,
          sum(vsc.valorServico*c.cotacaomoeda) as Valor_Serviço,
          count(s.nomeservico) as qtd,
          EXTRACT(MONTH FROM SS.DATAHORAFIM) AS MESSERVICO
        FROM solicitacaoservico ss
        INNER JOIN SERVICOCONTRATO SC ON SC.IDSERVICOCONTRATO = SS.IDSERVICOCONTRATO
        INNER JOIN VALORSERVICOCONTRATO VSC ON VSC.IDSERVICOCONTRATO = SC.IDSERVICOCONTRATO
        INNER JOIN CONTRATOS C ON C.IDCONTRATO = SC.IDCONTRATO
        INNER JOIN SERVICO S ON S.IDSERVICO = SC.IDSERVICO
        left JOIN CATEGORIASERVICO CC ON S.IDCATEGORIASERVICO = CC.IDCATEGORIASERVICO
        WHERE ss.datahorafim BETWEEN '2017-03-01 00:00:00' AND '2017-03-31 23:59:59.999'
        AND UPPER(SS.SITUACAO) = UPPER('FECHADA')
        GROUP BY case when cc.nomecategoriaservico = 'name1' or name_col = 'name3' then 'name1or3' else cc.nomecategoriaservico end, EXTRACT(MONTH FROM SS.DATAHORAFIM)

将两个具有不同P键值的特定行相加。 PostgreSQL的

1 个答案: