Question

for emp in employee:
  contract_id = contract_pool.search(cr, uid, [('employee_id','=',emp.employee_id.id)], context=context)
     for contract in contract_pool.browse(cr, uid, contract_id, context=context):
        for attendance in contract.working_hours.attendance_ids:
          if day == attendance.dayofweek:
             planned_time_in = attendance.hour_from
             planned_time_out = attendance.hour_to
             planned_wrkng_hrs = planned_time_out - planned_time_in
             print planned_wrkng_hrs
  actual_time_in = emp.time_in
  actual_time_out = emp.time_out
  actual_wrkd_hrs = actual_time_out - actual_time_in
  print actual_wrkd_hrs
  hrs_short = planned_wrkng_hrs - actual_wrkd_hrs
  print hrs_short

这给出了输出为：
9.00
8.57
0.43
我怎样才能得到：
9:00
8:57
00:03
浮动值在这里被减去而不是时间。

Answer 1

假设时间值的格式与您的示例类似，您可以通过执行类似

的操作将其转换为分钟 - 午夜

time_in_mins = int(original_time) * 60 + (original_time - int(original(time)) * 100

然后使用新的＆＃34;标准化＆＃34;进行所有计算。值，然后将其转换回您首选的格式以供显示或存储。

Answer 2

希望这能帮到你^^：

from datetime import time
from datetime import datetime, date
import math
# on thing hour part cannot be more that 23 and 
first_time = 23.5
secend_time = 23.0

# convert float to hour and minute
f_hour, f_time = int(math.floor(first_time)), int(round((first_time % 1) * 60))
s_hour, s_time = int(math.floor(secend_time)), int(round((secend_time % 1) * 60))
# create datetime object to perform substraction
duration = datetime.combine(date.min,time(f_hour,f_time))- datetime.combine(date.min,time(s_hour,s_time))
print "total minute between this two time is %s minutes " % (duration.total_seconds() / 60)

结果：

total minute between this two time is 30.0 minutes

Odoo - 减去2＆＃34;时间＆＃34; python中的字段

2 个答案: