Question

我正在尝试进行一个查询，返回一个人工作的分钟数。一个人可以在同一天有很多条目和退出。我想知道进入和退出之间的总分钟数。

这张表格的图片：

例如：我希望20498090R返回79分钟

我尝试使用此查询，但效果不佳：

SELECT  Empleado,
    DATEDIFF("mi", Hora, NextDate)
FROM    (   SELECT  Empleado,
                Hora,
                (   SELECT  MIN(Hora) 
                    FROM    [dbo].[Fichajes] T2
                    WHERE   T2.Empleado = T1.Empleado 
                    AND     T2.Hora > T1.Hora
                ) AS NextDate
        FROM    [dbo].[Fichajes] T1

    ) AS T

使用此查询：

12212332W --> 
20498090R --> 4
41435568N --> 6
20498090R --> 7055
41435568N --> 
20498090R --> 75
20498090R -->

Answer 1

从员工订购的登录表和时间戳创建CTE，并指定行号。现在，您可以将CTE加入到自身中，仅查找员工登录并注销的行。然后你可以找到工作的分钟数，并将它们加起来。

;with cte
as (select f.Empleado, f.Hora, f.Entrada, ROW_NUMBER() over (order by f.Empleado, f.Hora) RowNum
    from Fichajes f)

select c1.Empleado, SUM(DATEDIFF(mi, c1.Hora, c2.Hora)) MinutesWorked
from cte c1
join cte c2 on c2.Empleado = c1.Empleado and c2.RowNum = c1.RowNum + 1 and c1.Entrada = 1 and c2.Entrada = 0
group by c1.Empleado

DEMO

Answer 2

使用像这样的游标：

宣告@LV_EMP_CUR CURSOR
DECLARE @LV_EMP VARCHAR（32）

宣告@LV_MINUTES FLOAT

SET @ LV_EMP_CUR = CURSOR FOR 选择Empleado FROM TABLE_NAME

                    OPEN @LV_EMP_CUR FETCH NEXT FROM @LV_EMP_CUR INTO @LV_EMP
WHILE @@FETCH_STATUS = 0
    BEGIN

        DECLARE @DT DATETIME
        SET @DT = (SELECT HORA FROM TABLE_NAME WHERE EMPLEADO=@LV_EMP)

        SET @LV_MINUTES= @LV_MINUTES + SELECT CAST(@DT AS TIME)

        FETCH NEXT FROM @LV_EMP_CUR INTO @LV_EMP
    END
CLOSE @LV_EMP_CUR
DEALLOCATE @LV_EMP_CUR

Answer 3

我使用了一个sql窗口函数LEAD来查找下一条记录并按用户和日分区。然后计算同一用户和同一日期两次之间的工作分钟数。

将数据插入临时表以分组并获取总工作分钟数。您可以在最终选择查询之前使用 SELECT * FROM #tempTime; 来查看临时表中的结果。它提供了代码是否正常工作的想法。

最终代码：

IF OBJECT_ID('dbo.Fichajes') IS NULL 
CREATE TABLE dbo.Fichajes(
    [Empleado] [varchar](20) NULL,
    [Obra] [varchar](20) NULL,
    [Hora] [datetime2](7) NULL,
    [Entrada] [bit] NULL,
    [Motivo] [varchar](20) NULL,
    [Activated] [bit] NULL
) 
;

INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'12212332W', N'PRY12345', CAST(N'2017-04-17 12:03:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-20 12:21:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-20 12:25:00.0000000' AS DateTime2), 0, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'41435568N', N'PRY12345', CAST(N'2017-04-20 12:23:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'41435568N', N'PRY12345', CAST(N'2017-04-20 12:29:00.0000000' AS DateTime2), 0, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-25 10:00:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-25 11:15:00.0000000' AS DateTime2), 0, NULL, NULL)


IF OBJECT_ID('tempdb..#tempTime') IS NOT NULL DROP TABLE #tempTime;
with c1 AS
(
    SELECT 
         [Empleado]
        ,[Obra]
        ,[Entrada]
        ,[Motivo]
        ,[Activated]
        ,CONVERT(date, Hora) AS [Date]
        ,CONVERT(time, Hora, 114) AS [Time]
        ,[Hora] 
    FROM [dbo].[Fichajes]
)
SELECT 
     [Empleado]
    ,[Hora]
    ,LAG( [Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC) AS PreviousRecord
    ,LEAD( [Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC) AS NextRecord
    ,DATEDIFF(MINUTE,  [Hora], LEAD( [Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC)) AS [Minutes]
INTO #tempTime
FROM c1
;

SELECT
    [Empleado]
    ,SUM([Minutes]) AS WorkingMinutes
FROM #tempTime
GROUP BY [Empleado]
;

Sql记录之间的总分钟数

3 个答案: