Question

我有一份文件语料库和一系列单词。我想在语料库上运行for循环，以便循环从语料库中顺序删除列表中的每个单词。

一些复制数据：

library(tm)
m <- cbind(c("Apple blue two","Pear yellow five","Banana yellow two"),
             c(1, 2, 3))
tm_corpus <- Corpus(VectorSource(m[,1]))
words <- as.list(c("Apple", "yellow", "two"))

tm_corpus现在是一个由3个文档组成的语料库对象：

<<SimpleCorpus>>
Metadata:  corpus specific: 1, document level (indexed): 0
Content:  documents: 3

words是3个单词的列表：

[[1]]
[1] "Apple"

[[2]]
[1] "yellow"

[[3]]
[1] "two"

我尝试了三种不同的循环。第一个是：

tm_corpusClean <- tm_corpus
for (i in seq_along(tm_corpusClean)) {
  for (u in seq_along(words)) {
    tm_corpusClean[i] <- tm_map(tm_corpusClean[i], removeWords, words[[u]])
  }
}

返回以下错误7次（编号为1-7）：

Error in x$dmeta[i, , drop = FALSE] : incorrect number of dimensions
In addition: Warning messages:
1: In tm_corpusClean[i] <- tm_map(tm_corpusClean[i], removeWords,                 
words[[u]]) :
  number of items to replace is not a multiple of replacement length
2: In tm_corpusClean[i] <- tm_map(tm_corpusClean[i], removeWords,         
words[[u]]) :
  number of items to replace is not a multiple of replacement length
[...]

第二个是：

tm_corpusClean <- tm_corpus
for (i in seq_along(words)) {
  for (u in seq_along(tm_corpusClean)) {
    tm_corpusClean[u] <- tm_map(tm_corpusClean[u], removeWords, words[[i]])
  }
}

返回错误：

Error in x$dmeta[i, , drop = FALSE] : incorrect number of dimensions

最后一个循环是：

tm_corpusClean <- tm_corpus
for (i in seq_along(words)) {
  tm_corpusClean <- tm_map(tm_corpusClean, removeWords, words[[i]])
}

这实际上返回一个名为tm_corpusClean的对象，但此对象只返回第一个文档而不是所有原始文档：

inspect(tm_corpusClean[[1]])

<<PlainTextDocument>>
Metadata:  7
Content:  chars: 6

 blue

我哪里错了？

Answer 1

在我们进行顺序删除之前，请测试tm_map是否适用于您的示例：

obj1 <- tm_map(tm_corpus, removeWords, unlist(words))
sapply(obj1, `[`, "content")

$`1.content`
[1] " blue "

$`2.content`
[1] "Pear  five"

$`3.content`
[1] "Banana  "

接下来，使用lapply一次删除一个单词，即"Apple", "yellow", "two"：

obj2 <- lapply(words, function(word) tm_map(tm_corpus, removeWords, word))
sapply(obj2, function(x) sapply(x, `[`, "content"))

          [,1]                [,2]             [,3]              
1.content " blue two"         "Apple blue two" "Apple blue "     
2.content "Pear yellow five"  "Pear  five"     "Pear yellow five"
3.content "Banana yellow two" "Banana  two"    "Banana yellow "

请注意，生成的语料库位于嵌套列表中（两个sapply用于查看内容的原因）。

循环通过tm语料库而不会丢失语料库结构

1 个答案: