Question

我正在尝试在一行和几个类别中绘制许多IntervalBarItem。在Oxyplot中，Categoryaxis将ForevalBarSeries中的一个IntervalBarItem绘制到该行中。因此，如果我有三个系列，每个有4个项目 - 我得到4个类别，3个BarItems（Series1，Series2，Series3）。但是我想要3个类别 - 每个类别对应一个系列中的4个项目 - 我可以通过为每个项目设置CategoryIndex-Property来获得此结果。在这里，我得到IndexOutOfRangeException - 通过在循环中设置Index-Property。

MCVE：

XAML的文件：

<Window x:Class="BarSeries_Stacked.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:BarSeries_Stacked"
        xmlns:oxy="http://oxyplot.org/wpf"
        mc:Ignorable="d"
        Title="MainWindow" Height="350" Width="525">
    <Grid>
        <oxy:PlotView Name="plot" />
    </Grid>
</Window>

CS-文件：

namespace BarSeries_Stacked
{
    /// <summary>
    /// Interaktionslogik für MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            SetUpPlot();
        }

        private void SetUpPlot()
        {

            DateTime start = new DateTime(2017, 1, 1, 15, 0, 0);
            DateTime start1 = new DateTime(2017, 1, 1, 15, 15, 0);
            DateTime start2 = new DateTime(2017, 1, 1, 15, 20, 0);
            DateTime start3 = new DateTime(2017, 1, 1, 15, 45, 0);

            DateTime end = new DateTime(2017, 1, 1, 15, 10, 0);
            DateTime end1 = new DateTime(2017, 1, 1, 15, 17, 0);
            DateTime end2 = new DateTime(2017, 1, 1, 15, 30, 0);
            DateTime end3 = new DateTime(2017, 1, 1, 15, 59, 0);

            var model = new PlotModel();
            model.IsLegendVisible = false;

            model.Axes.Add(new OxyPlot.Axes.DateTimeAxis() { Position = AxisPosition.Bottom });
            model.Axes.Add(new OxyPlot.Axes.CategoryAxis() { Position = AxisPosition.Left });
            plot.Model = model;


            var series = new OxyPlot.Series.IntervalBarSeries { Title = "Series 1", StrokeThickness = 1 };
            model.Series.Add(series);

            series.Items.Add(new IntervalBarItem { CategoryIndex = 0, Start = start.ToOADate(), End = end.ToOADate() });
            series.Items.Add(new IntervalBarItem { CategoryIndex = 0, Start = start1.ToOADate(), End = end1.ToOADate() });

            for (int i = 0; i < 10; i++)
            {
                var series2 = new OxyPlot.Series.IntervalBarSeries { Title = "Series "+i.ToString(), StrokeThickness = 1 };
                series2.Items.Add(new IntervalBarItem { CategoryIndex = i, Start = start2.AddHours(i).ToOADate(), End = end2.AddHours(i).ToOADate() });
                series2.Items.Add(new IntervalBarItem { CategoryIndex = i, Start = start3.AddHours(i).ToOADate(), End = end3.AddHours(i).ToOADate() });
                model.Series.Add(series2);
            }

        }
    }
}

仅用于测试将其他索引（例如1）作为CategoryIndex

Answer 1

这取决于你究竟想要做什么，但修复你的循环的一种方法是：

for (int i = 0; i < 10; i++)
{
    var series2 = new OxyPlot.Series.IntervalBarSeries { Title = "Series " + i.ToString(), StrokeThickness = 1 };
    model.Series.Add(series2);
    for (int j = 0; j < i; j++)
        series2.Items.Add(new IntervalBarItem { CategoryIndex = j, Start = start2.AddHours(i).ToOADate(), End = end2.AddHours(i).ToOADate() });
}

这里的核心问题是，如果每个系列只添加2 CategoryIndex = 8，则无法添加IntervalBarItem。

修复循环的另一种方法：

for (int i = 0; i < 10; i++)
{
    var series2 = new OxyPlot.Series.IntervalBarSeries { Title = "Series " + i.ToString(), StrokeThickness = 1 };
    series2.Items.Add(new IntervalBarItem { CategoryIndex = 0, Start = start2.AddHours(i).ToOADate(), End = end2.AddHours(i).ToOADate() });
    series2.Items.Add(new IntervalBarItem { CategoryIndex = 1, Start = start3.AddHours(i).ToOADate(), End = end3.AddHours(i).ToOADate() });
    model.Series.Add(series2);
}

还有一个，只是为了确保：

for (int i = 0; i < 10; i++)
{
    var series2 = new OxyPlot.Series.IntervalBarSeries { Title = "Series " + i.ToString(), StrokeThickness = 1 };
    for (int j = 0; j < random.Next(0, i); j++)
        series2.Items.Add(new IntervalBarItem { CategoryIndex = j, Start = start2.AddHours(i).ToOADate(), End = end2.AddHours(i).ToOADate() });
    model.Series.Add(series2);
}

编辑：一个系列的一个系列：

 for (int i = 0; i < 10; i++)
        {
            var series2 = new OxyPlot.Series.IntervalBarSeries { Title = "Series " + i.ToString(), StrokeThickness = 1 };
            model.Series.Add(series2);
            for (int j = 0; j < i+1; j++)
                series2.Items.Add(new IntervalBarItem { CategoryIndex = i, Start = start2.AddHours(j).ToOADate(), End = end2.AddHours(j).ToOADate() });
        }

尝试在循环

1 个答案: