Question

下午好，我想请求你的帮助。

请帮我将此查询应用到Laravel查询生成器中。我只知道如何使用原始查询查询数据库。

查询：

SELECT users.first_name, users.last_name, users.id as userID, bookmarks.id, 
products.title, products.price, products.id AS productID FROM users,
products, bookmarks WHERE bookmarks.user_id = $user_id AND products.id = 
bookmarks.product_id AND users.id = products.user_id;

感谢那些能帮助我的人。

Answer 1

Use this Laravel Query.

 $response = DB::table('users as u')->select(
                'u.id as userId',
                'u.first_name',
                'u.last_name',
                'b.id as bookmarkId',
                'p.id as productId',`enter code here`
                'p.title',
                'p.price'
            )
                ->leftjoin('bookmarks as b', 'b.user_id', '=', 'u.id')
                ->leftjoin('products as p', 'p.user_id', '=', 'u.id')
                ->where('u.id', $userId)->get();

Answer 2

   $result = DB::select(DB::raw('custom_query'));
   $user_name = $result[0]->first_name.' '.$result[0]->last_name;

Answer 3

将userss.first_name，users.last_name，users.id选为userID， bookmarks.id，products.title，products.price，products.id AS productID FROM用户，产品，书签WHERE bookmarks.user_id = $ user_id AND products.id = bookmarks.product_id AND users.id = products.user_id;

您可以使用eloquent with方法，只需访问关系，但如果您想要laravel查询方法。您可以使用DB :: raw来拥有自己的原始查询。

DB::select(DB::raw("Select a.first_name, a.last_name, a.id as user_id, b.id, c.title, c.price, c.id from users as a INNER JOIN bookmarks as b on b.user_id = $user_id INNER JOIN Products as c on c.id = b.product_id where  user_id = c.user_id"));

这只是一个示例，它仍然取决于您如何操纵查询。

爱 Poop

Laravel Query Builder加入

3 个答案: