Question

我有一组数据，我想建立一个带有自定义属性名称的新数据，现有的数据集已嵌套，这也是我需要将其规范化以适应我自己的原因之一使用

说我有这套现有数据

[{
name:"abc",
company:{name:"abc company",age_of_company:1},
age: 19
}]

我想构建一个新的对象数组，其中属性和嵌套级别将是这样的

[{
ceo_name:"abc",
company_name:"abc company",
age: 19
}]

我被困了

const newData = existingData.map(obj => (
//obj.company.name I don't know what to do here
)

Answer 1

您可以按如下方式对传递给map的函数的参数进行解构：

existingData.map(
  ({age, name: ceo_name, company: {name: company_name}}) =>
    ({ceo_name, company_name, age}))

Answer 2

const newData = existingData.map(obj => (
    {
        ceo_name: obj.name,
        company_name: obj.company.name,
        age: obj.age
    }
))

Answer 3

试试这个

[{
    name:"abc",
    company:{name:"abc company",age_of_company:1},
    age: 19
}].map(element => {
    return {
        ceo_name: element.name,
        company_name: element.company.name,
        age: element.age
    }
})

Answer 4

// ...

$collection = collect($collection);

$page = 1;
$perPage = 10;

$paginate = new LengthAwarePaginator($collection->forPage($page, $perPage), $collection->count(), $perPage, $page, ['path'=>url('api/products')]);

使用es2015的地图构建新的对象数组

4 个答案: