Question

我有一系列字典，他们看起来像这样：

{
Place = "here";
Type = Any;
timeRegisted = "04-24-2017 10:42";
},

{
Place = "there";
Type = Any;
timeRegisted = "04-24-2017 09:52";
},

{
Place = "overThere";
Type = Any;
timeRegisted = "04-24-2017 05:55";
},

{
Place = "somewhere";
Type = Any;
timeRegisted = "04-24-2017 06:15";
},
{
Place = "here";
Type = Any;
timeRegisted = "04-24-2017 06:15";
},
{
Place = "overthere";
Type = Any;
timeRegisted = "04-24-2017 05:42";
},

但是我想根据timeRegisted对数组进行排序。任何人都知道我可以根据时间对数组进行排序吗？

我非常感谢你的帮助。

Answer 1

以下代码将对您的数组进行排序。它确实假设timeRegistered将转换为有效的日期。您应该添加对formatter.date返回的值的检查为非零

let array2 = array.sorted(by:{let formatter = DateFormatter()
    formatter.dateFormat = "MM-dd-yyyy HH:mm"
    return formatter.date(from:$0.timeRegisted)! < formatter.date(from:$1.timeRegisted)!})

Answer 2

我正在使用Alamofire和SwiftyJSON。

        Alamofire.request(yourURL, method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: [:])
            .responseJSON { response in

                switch(response.result) {
                case .success(_):

                    var responseObject = JSON(response.result.value!).arrayValue

        let dateFormatter = DateFormatter()
        dateFormatter.dateFormat = "MM/dd/yyyy HH:mm"

   responseObject = responseObject.sorted(by: { [dateFormatter] (item1, item2) -> Bool in
            return dateFormatter.date(from: item1["timeRegisted"].stringValue)!.compare(dateFormatter1.date(from: item2["timeRegisted"].stringValue)!) == ComparisonResult.orderedDescending
        })

        print(responseObject)
        break

                    case .failure(_):
                        print(response.result.error ?? "Response is nil")
                        break
                    }
            }

使用日期排序字典数组

2 个答案: