Question

以下是每隔几分钟记录10台设备。我需要为每个id返回唯一的记录集，每个都应该只是最新的。

如何使用弹性搜索或其他任何解决方案都可以做到这一点。

{
    {id: 1, time: 12345}, 
    {id: 2, time: 12346}, 
    {id: 1, time: 12347}, 
    {id: 2, time: 12348}, 
    {id: 1, time: 12349}, 
    {id: 3, time: 12350}, 
    ... // 10 different ids and 10000 records
}

Answer 1

这是我能得到的尽可能接近。如果您在原始数据集中说出超过10个唯一ID，则不确定如何选择返回哪10个结果。

＆＃13;

var rawData = [
    {id: 1, time: 12345}, 
    {id: 2, time: 12346}, 
    {id: 1, time: 12347}, 
    {id: 2, time: 12348}, 
    {id: 1, time: 12349}, 
    {id: 3, time: 12350}, 
    {id: 4, time: 12351}, 
    {id: 2, time: 12352}, 
    {id: 7, time: 12353}, 
    {id: 5, time: 12354}, 
    {id: 3, time: 12355}, 
    {id: 6, time: 12356}, 
    {id: 3, time: 12357}, 
    {id: 7, time: 12358}, 
    {id: 6, time: 12359}, 
    {id: 9, time: 12360}
]

var maxSet = {};
// Get all of the max values
rawData.forEach(function (currentValue, index, array) {
  var currentMax = maxSet[currentValue.id] || null;
  if(currentMax) {
    if(currentValue.time > currentMax){
      maxSet[currentValue.id] = currentValue.time;
    }
  } else {
    maxSet[currentValue.id] = currentValue.time;
  }
});
console.log(maxSet);
// Convert back to object if necessary
var keys = Object.keys(maxSet);
var resultObjs = [];
for(var key in keys) {
    resultObjs.push({id: keys[key], time: maxSet[keys[key]]});
}
console.log(resultObjs);

＆＃13;

Answer 2

我认为，你正在寻找这个，它会给最大time一个唯一的id： -

{
    "_source":false,
    "aggs": {
        "byId": {
            "terms": {
                "field": "id"
            },
            "aggs": {
                "byTime": {
                    "max": {
                        "field": "time"
                    }
                }
            }
        }
    }
}

如何用多个参数过滤json对象？

2 个答案: